if it rains tomorrow, the probability is 0.8 that john will practice the piano. if it does not rain tomorrow, there is only a .4
chance that john will practice. if there is a 60% that it will rain tomorrow, what is the probability that John will practice his piano lesson? i'm supposed to use a tree diagram to solve this ...?
P(J / R) = P (J and R) / P(R) <span>0.8 = P (J and R) / 0.6 </span> <span>P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining] </span>
<span>P(J / NR) = P (J and NR) / P(NR) </span> <span>0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4 </span> <span>P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining] </span>
<span>Hence; </span> <span>Propability of John practicing regardless of weather condition is </span>