Find the angle sum of the irregular polygon using the formula S= 180(n-2).
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Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
Y = - 10x has a negative slope, m = -10, and a y-intercept of (0, 0).
The graph includes the following points:
{(-2, 20), (-1, 10), (0, 0), (1, -10), (2, -20)}.
Attached is a screenshot of the graph, where it includes the y-intercept crossing along the point of origin, (0, 0).
Please mark my answers as the Brainliest, if you find this helpful :)
The graph includes the following points:
{(-2, 20), (-1, 10), (0, 0), (1, -10), (2, -20)}.
Attached is a screenshot of the graph, where it includes the y-intercept crossing along the point of origin, (0, 0).
Please mark my answers as the Brainliest, if you find this helpful :)