I believe the answer is D because the pathagreom theorum proves it true (excuse my terrible grammar)
The temperature was 1 because of you add them
-11+12=1
Answer:
The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Step-by-step explanation:
The given expression is:
2q²-5pq-2q+5p
Make a pair of first two terms and last two terms:
(2q²-5pq) - (2q-5p)
Now factor out the common factor from each group.
Note that there is no common factor in second group. So we will take 1 as a common factor.
q(2q-5p) -1(2q-5p)
Now factor the polynomial by factoring out the G.C.F, 2q-5p
(2q-5p) (q-1)
Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
9514 1404 393
Answer:
no solution
Step-by-step explanation:
The equations describe parallel lines. There are no values of x and y that will satisfy both equations.
In standard form, the two equations are ...
3x +7y = 21
3x +7y = -42 . . . . . with positive leading coefficient
If (x, y) values satisfy the first equation, they cannot satisfy the second equation, and vice versa.
Answer:
wat is this, my g this looks like a test
