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andreev551 [17]
3 years ago
14

jane spent $15.75 to purchase cookies and brownies for 25 of her classmates. Cookies cost $0.50 and brownies cost $0.75. How man

y of each type of snack did Jane buy?
Mathematics
2 answers:
AlladinOne [14]3 years ago
7 0

im not sure

Step-by-step explanation:s


Alex3 years ago
4 0
Idk ... 30 cookies, 1 brownie
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In a probability experiment, Karen flipped a coin 58 times. The coin landed on heads 33 times. What percentage of the coin flips
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3 years ago
The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 900 vot
Stells [14]

Answer:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

Step-by-step explanation:

Information given

n=900 represent the random sample selected

\hat p=0.75 estimated proportion of residents favored annexation

p_o=0.72 is the value that we want to test

represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:  

Null hypothesis:p\leq 0.72  

Alternative hypothesis:p > 0.72  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

3 0
3 years ago
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