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ryzh [129]
2 years ago
8

Point P, Q, and R are shown on the number line. What is the distance between point P and point Q? P(-76) Q(-24) R(0) A) 52 units

B) 63 units C) 70 units D) 100 units
Mathematics
2 answers:
Sever21 [200]2 years ago
5 0

Answer:

Option A is correct.

The distance between P and Q along the number line = 52 units

Step-by-step explanation:

Three points are given as having the coordinates P(-76) Q(-24) R(0) on the number line

The distance between two point on the number line is given as the difference between the two points.

PQ = point Q - point P = -24 - (-76) = 52 units.

Hope this Helps!!

MissTica2 years ago
5 0

Answer:

The correct option is;

A) 52 units

Step-by-step explanation:

Numbers on the number line progress from lowest value to highest value with the magnitude increasing in both ways from the zero mark. That is, numbers on the left of zero mark, (negative numbers) increase as we progress to the left while numbers on the right of the zero mark, (positive numbers) increase as we progress to the right.

Here we have point P = -76 and

Point Q = -24

Therefore Q > P

Hence the distance from P to Q is

Q - P = -24 - (-76) = 52.

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yes, the given relation is a function.

Step-by-step explanation:

The given relation is

{(–3, –2), (–1, 0), (1, 0), (5, –2)}

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Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
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Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
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For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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