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Annette [7]
3 years ago
9

What is the value of x in the equation 0.2(x + 1) + 0.5x = –0.3(x – 4)?

Mathematics
2 answers:
Alla [95]3 years ago
8 0
0.2(x+1)+0.5x=-0.3(x-4)
Expand the brackets
0.2x+0.2= -0.3x+1.2
Subtract 0.2 from each side
0.2x= -0.3x+1
Add 0.3 to each side
0.5x=1
Divide by 0.5 on each side
x= 1 ÷ 0.5 =2
To check, you can substitute 2 into the places of x
kotykmax [81]3 years ago
6 0

Answer:  x=1

<em><u>Step-by-step explanation:</u></em>

0.2(x+1) + 0.5x= -0.3(x-4)

Distribute the 0.2 to the parentheses

0.2x + 0.2 + 0.5= -0.3(x-4)

Distribute the -0.3 to the parentheses

0.2x + 0.2 + 0.5= -0.3x + 1.2

Combine Like Terms

0.7x + 0.2= -0.3x + 1.2

Move the variable to one side

(i picked to move the -0.3 because it is negative but you should be able to do it either way)     x + 0.2 = 1.2

Use subtraction property of equality to get the variable by itself

x + 0.2 = 1.2

   -0.2     -0.2

x= 1

Check it by plugging 1 wherever x appears in the original equation and solve it normally.

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Write an equation of the Ferris WheelSydney wants to ride a Ferris wheel that has a radius of 60 feet and is suspended 10 feet a
zmey [24]

Answer:

a) y (t) = 70 -60 cos[\frac{2pi}{3}(t)]

b) y (t=1.25) = 70 -60 cos[\frac{2pi}{3}(1.25)] =121.96 ft

c) Is just a translation of th original graph.

y (t) = 70 -60 sin[\frac{2pi}{3}(t)]

Step-by-step explanation:

Data given

R= 60 ft represent the radius

D= 2*60 = 120 ft represent the diameter

Suspended x=10 ft above the ground

Rpm = 2 rev/6min = 1 rev/3 min

The friend start 1/4 after Sydney.

Part a

We can find the maximum and minimum point like this

Max = 120+10 ft = 130ft

Min= 10 ft

We add 10 ft to the maximum because we are 10 ft above the ground

Then we can find the amplitude:

2A= Max-Min= 130-10 = 120 ft

So then A = 60 ft

And the middle point would be given by:

M=\frac{Max+Min}{2}=\frac{130+10}{2}=70 ft

We have also the period given by T = 3minutes since we have 1 revolution each 3 minutes.

We need to write a function that describes a Sydney’s height above the ground as a function of the number of seconds. So then we need to take the middle point 70 ft and subtract the function in terms of the amplitude and the period.

The the number of wave is given byk = frac{2\pi}{T}=\frac{2\pi}{3}

And the general equation would be given by:

y (t) = 70 -A cos[\frac{2pi}{3}(t)]

And replacing we got:

y (t) = 70 -60 cos[\frac{2pi}{3}(t)]

Part b

For this case we just need to replace t =1.25 min and we got:

y (t=1.25) = 70 -60 cos[\frac{2pi}{3}(1.25)] =121.96 ft

Part c

We need to take in count that the midpoint is at y=0. With the transofrmation we have the midpoint at y=70 ft. And if we move 1/4 we can see that the graph for the friend is the sine graph of the original equation.

And we can se this on the plot attached. When t=0 for the cos function is t=0.75 for the sin function. And the equation for the friend would be given by:

y (t) = 70 -60 sin[\frac{2pi}{3}(t)]

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