Write the equation of a line that is perpendicular to the given line and that passes through the given point.
1 answer:
-3x-6y=17
-6y=3x+17
y=-x/2-17/6 so the slope of the line is -1/2
For another line to be perpendicular to this one the product of their slopes must equal -1
(-1/2)m=-1, m=2 so the perpendicular line will have a slope of 2...
y=2x+b, using point (6,3) we can solve for b...
3=2(6)+b
3=12+b
b=-9 so
y=2x-9
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