Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

Answer 1

-3x-6y=17

-6y=3x+17

y=-x/2-17/6 so the slope of the line is -1/2

For another line to be perpendicular to this one the product of their slopes must equal -1

(-1/2)m=-1, m=2  so the perpendicular line will have a slope of 2...

y=2x+b, using point (6,3) we can solve for b...

3=2(6)+b

3=12+b

b=-9 so

y=2x-9