Answer:
1. r=anything
2. d=6
3. b=4
Step-by-step explanation:
Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Circle = (x-h)^2 + (y-k)^2 = r^2
Center is (h,k) h = -5, k = 2
Radius is 4, r = 4
(x - -5)^2 + (y - 2)^2 = 4^2
(x + 5)^2 + (y - 2)^2 = 16
Answer:
The other two vertices are (4 , -2) and (4 , 2)