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nataly862011 [7]
3 years ago
7

I WILL GIVE YOU BRAINLIEST

Mathematics
1 answer:
Mila [183]3 years ago
3 0
The probability of picking blue is stated as 2/10 which can be reduced to 1/5
 
 multiply the number of times they pick a marble ( shown as 200) by the probability of picking a blue one ( 1/5)

200 x 1/5 = 200 / 5 = 40

Quinn can expect to pick blue 40 times

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there are 15 blue jays and 14 oriels that wish to rest on branches of three older trees each of the trees will have at least 4 b
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The largest number of Bird in the tree could be 14
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I don't understand how to do this. Can someone help?
miskamm [114]
Time used for the call to Zurich: ($5-$1.25)/$0.25=15 minutes
15minutes+3minutes=18minutes
Time used for the call to London: ($7.25-$1.25)/$0.25=24 minutes
24minutes+3minutes=27minutes
Difference between the two calls:27-18=9minutes
3 0
3 years ago
Solve the simultaneous equations<br> 5y−4x=8<br> y+x=7<br><br> x= ?<br> y= ?
inna [77]

Answer:

x=3 y=4

Step-by-step explanation:

5(4)=20

4(3)= 12

20-12=8

4+3=7

4 0
3 years ago
Read 2 more answers
Evaluate -a - 12a^2 for a = -1<br><br> a. -13<br> b. 13<br> c.-11
Gelneren [198K]

C

substitute a = - 1 into the expression

- (- 1) - 12(- 1)² = 1 - (12 × 1 ) = 1 - 12 = - 11 → C


8 0
3 years ago
Read 2 more answers
A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gi
inessss [21]

Answer:

\frac{1429}{120} or 11\frac{109}{120}

Step-by-step explanation:

Given:

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.

Remaining peaches = 4

We need to find the original number of peaches in the basket.

The farmer gives the total number of peaches = \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7

Let x be the former gives the total number of peaches

We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.

x = \frac{120}{120}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7)

x = \frac{1}{120}(\frac{120}{3}+\frac{120}{4}+\frac{120}{5}+\frac{120}{8}+7\times 120)

x = \frac{1}{120}(40+30+24+15+840)

x = \frac{1}{120}(949)

x = \frac{949}{120}

We add the remaining peaches by given peaches for the original number of peaches in the basket.

Original number of peaches = \frac{949}{120}+4

Original number of peaches = \frac{949+4\times 120}{120}

Original number of peaches = \frac{949+480}{120}

Original number of peaches = \frac{1429}{120}

Original number of peaches = 11\frac{109}{120}

Therefore the original number of peaches in the basket is \frac{1429}{120} or 11\frac{109}{120}

5 0
3 years ago
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