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Scrat [10]
3 years ago
7

Solving and graphing systems of equations

Mathematics
1 answer:
dusya [7]3 years ago
3 0
Hey Jackson!

-4x + 3y = 3
y = 2x + 1

Ok so what we need to do is solving y= 2x + 1 for y.

So let's start by using the substitution method :)

Substitute 2x + 1 for y in -4x + 3y = 3

-4x+ 3y = 3

-4x + 3(2x + 1) = 3

-4x + (3)(2x) + (3)(1) = 3

-4x + 6x + 3 = 3

2x + 3 = 3

Subtract 3 on both sides

2x + 3 - 3 = 3 - 3

2x = 0

x = 0/2

x = 0

So now since we find the number for x, we gonna use it to help us find the value for y.

To find y, we need to substitute 0 for x in y = 2x + 1

y = 2x + 1

y = 2(0) + 1

y = 0 + 1

y = 1

Thus,

The answer is: y = 1 and x = 0

How to graph?

You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1

I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)

Let me know if you have any questions. As always, it is my pleasure to help students like you!


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Determine the solution set of each equation
maks197457 [2]

A=x1 = -8,x2 =2, B=x1= -5,x2=5, C=y1 = -4, y2 =5, D=y 18 over 5

alternative form

y=3 3over 5, =3.6

And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

x2 +8x-2x-16=0

factor out x for the expression

xx(x+8)-2x-16=0

factor out -2 from the expression

xx(x+8)- 2(x+8)=0

factor out x+8 from the expression

(x+8)x(x- 2)=0

when the product of factors equals 0,at least one factor is 0

x+8=0

x - 2=0

solve the equation for x

x= -8

x - 2=0

solve the equation for x

x= -8

x =2

the equation has 2 solution

x1 = -8,X2 =2

answer is

x1 = -8,x2 =2

Or

Solving steps:Number of solution

x²+6x-16=0

Determine the number of solution using the

discriminant D =b²- 4ac

D =6²- 4x1x(-16)

simply the expression

D=100

Since D>0, the quadratic equation has 2 real solution

2 real solution

Answer is

2 real solution

Question B

Solving steps:Solve the quadratic equation

x²-25=0

Move the constant to the right-hand side and change its sign

x²=25

Take the square root of both sides of the equation and remember to use both positive and negative roots

x=+5

Write the solutions,one with a +sign and one with a -sign

x= -5

x=5

The equation has 2 solutions

x1= -5,x2=5

the answer is

x1= -5,x2=5

Or

Solving steps:Number of solution

x²-25=0

Determine the number of solutions using the discriminant D=b²- 4ac

D=0²- 4x1x(-25)

Simply the expression

D=100

Since D>0,the quadratic equation has 2real solutions

Answer is

2real solutions

answer of question C is

y1 = -4, y2 =5

Answer of question D is

y 18 over 5

alternative form

y=3 3over 5, =3.6

Answer of question E is

x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667

Please mark as brainiest

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3 years ago
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