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3 years ago

What is the equation in standard form of the line which passes through (-2, 6) and has a slope of -1?

Mathematics

1 answer:

jekas [21]3 years ago

4 0

Answer:

x + y = 4

Step-by-step explanation:

To write the equation of the line use the point slope form. Then convert to the standard from. Begin by substituting m = -1 and (-2,6).

$y - y_1 = m(x-x_1)\\y - 6 = -1(x --2)\\y - 6 = -1(x+2)\\y - 6 = -x -2\\x + y - 6 = -2\\x + y = 4$

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Simplify the ratio 24:81

gizmo_the_mogwai [7]

Answer:

8 to 27

Step-by-step explanation:

3 0

2 years ago

cora says she doesn't need to know the y-intercept of a line to write its equation, just its slope and some other point on the l

Nadusha1986 [10]

Answer:

The equation of line with given slope that include given points is 3 y + x - 20 = 0

Step-by-step explanation:

According to Cora , if we know the slope and points on a line then we can write the equation of a line .

Since , The equation of line in slope-intercept form is

y = m x + c

<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>

So , From the statement said above it is clear that she is correct .

Now , Again

Given as :

Slope of a line is m = - $\frac{1}{3}$

That include points ( 2 , 6 )

Now from the equation of line as y = m x + c

∴ 6 = - $\frac{1}{3}$ ( 2 ) + c

Or, 6 = - $\frac{2}{3}$ + c

So , c = 6 + $\frac{2}{3}$

or, c = $\frac{18 + 2}{3}$

∴ c = $\frac{20}{3}$

So, The equation of line can be written as

y = - $\frac{1}{3}$ x + $\frac{20}{3}$

Or, 3 y = - x + 20

I.e 3 y + x - 20 = 0

Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer

8 0

3 years ago

Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1

natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$