2x+3y=6
subtract 2x from both sides.
3y=6-2x
divide by 3 on all sides.
y=2-2/3x
A + 2K = 8.75
2A + 5K = 19.75
Change the first expression so that we can subtract the As
2A + 5K = 19.75
2A+4K= 17.50
If the signs are the same, subtract one expression from another
K= 2.25
substitute K into any expression to get A
A+4.50= 8.75
Subtract 4.50
a=4.25
K=$2.50
A= $4.25
1 meter is 100 centimeters
10 millimeters is 1 centimeter
400 millimeters is 40 centimeters
100 + 85 + 40 = 225
225 centimeters
Hey listen kid I can’t answer your question I’m sorry I am just doing this because I need help with my math sorry
9514 1404 393
Answer:
it is application of the multiplication property of equality
Step-by-step explanation:
You can use "cross products" to solve any proportion. What looks like a "cross product" is just application of the multiplication property of equality. That property says the variable value is unchanged if both sides of the equation are multiplied by the same value.
For your fraction, the "cross product" is what you get when you multiply both sides of the equation by 500.
![\dfrac{18}{5}=\dfrac{x}{100}\qquad\text{given}\\\\\dfrac{18\cdot5\cdot100}{5}=\dfrac{x\cdot5\cdot100}{100}\qquad\text{multiply by $5\cdot100$}\\\\18\cdot100=5\cdot x\qquad\text{cancel common factors; looks like cross product}](https://tex.z-dn.net/?f=%5Cdfrac%7B18%7D%7B5%7D%3D%5Cdfrac%7Bx%7D%7B100%7D%5Cqquad%5Ctext%7Bgiven%7D%5C%5C%5C%5C%5Cdfrac%7B18%5Ccdot5%5Ccdot100%7D%7B5%7D%3D%5Cdfrac%7Bx%5Ccdot5%5Ccdot100%7D%7B100%7D%5Cqquad%5Ctext%7Bmultiply%20by%20%245%5Ccdot100%24%7D%5C%5C%5C%5C18%5Ccdot100%3D5%5Ccdot%20x%5Cqquad%5Ctext%7Bcancel%20common%20factors%3B%20looks%20like%20cross%20product%7D)
__
Note that the next step here is to divide by the x-coefficient, the 5 that was in the left-side denominator.
![\dfrac{18\cdot100}{5}=x\qquad\text{divide by 5}](https://tex.z-dn.net/?f=%5Cdfrac%7B18%5Ccdot100%7D%7B5%7D%3Dx%5Cqquad%5Ctext%7Bdivide%20by%205%7D)
Please also note that this is exactly the same result you would get by multiplying the original equation by the original denominator of x.