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likoan [24]
3 years ago
6

Write an absolute value inequality that

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

All real numbers greater than or equal to -1 and less than or equal to 2

Step-by-step explanation:

Let

A_1 ------> the area of rectangle

A_2 ----> the area of triangle

we know that

\left|A_1-A_2\right|\le 6

<em>Find out the area of rectangle</em>

A_1=4(x+2)=(4x+8)\ units^2

<em>Find out the area of triangle</em>

A_2=(1/2)(4)(5)=10\ units^2

substitute

\left|(4x+8)-10\right|\le 6

Simplify

\left|4x-2\right|\le 6

<em>First case (positive value)</em>

+(4x-2) \leq 6

4x \leq 6+2

4x \leq 8

x \leq 2

<em>Second case (negative value)</em>

-(4x-2) \leq 6

Multiply by -1 both sides

(4x-2) \geq -6

(4x \geq -6+2

4x \geq -4

x \geq -1

therefore

The solution for x is the interval -----> [-1,2]

All real numbers greater than or equal to -1 and less than or equal to 2

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7r-5r+8=9r+8-r translate to an equation, then solve
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Midsegment of any trapezoid is the line segment

1. that is parallel to pair of parallel side of trapezoid and

2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.

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