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likoan [24]
3 years ago
6

Write an absolute value inequality that

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

All real numbers greater than or equal to -1 and less than or equal to 2

Step-by-step explanation:

Let

A_1 ------> the area of rectangle

A_2 ----> the area of triangle

we know that

\left|A_1-A_2\right|\le 6

<em>Find out the area of rectangle</em>

A_1=4(x+2)=(4x+8)\ units^2

<em>Find out the area of triangle</em>

A_2=(1/2)(4)(5)=10\ units^2

substitute

\left|(4x+8)-10\right|\le 6

Simplify

\left|4x-2\right|\le 6

<em>First case (positive value)</em>

+(4x-2) \leq 6

4x \leq 6+2

4x \leq 8

x \leq 2

<em>Second case (negative value)</em>

-(4x-2) \leq 6

Multiply by -1 both sides

(4x-2) \geq -6

(4x \geq -6+2

4x \geq -4

x \geq -1

therefore

The solution for x is the interval -----> [-1,2]

All real numbers greater than or equal to -1 and less than or equal to 2

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