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4 years ago

Is 9/10ths bigger or smaller than 5/6th

Mathematics

1 answer:

ollegr [7]4 years ago

4 0

Answer:

9/10 > 5/6

Step-by-step explanation:

9/10 and 5/6

get them common deminators.

54/60 vs. 50/60

54 > 50

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The temperature in Boston was -15 on Saturday at 1:10pm.It increased by 2F every minute until 1:50pm.What was the temperature at

Temka [501]

The temperature was 65 F at 1:50 P.M.
150 - 110 = 40
40 x 2 = 80
80 - 15 = 65

4 0

4 years ago

What is the nearest ten and hundred 622

Zepler [3.9K]

622

rounded to nearest tens = 620
rounded to nearest hundreds = 600

8 0

3 years ago

Read 2 more answers

Your boss hands you a memo with a summary of the monthly data.

lisov135 [29]

Functions are used to represent tables and equations

The function that represents the number of imports is f(x) = 2x
The function that represents the number of exports is f(x) = 2 + x

<h3>How to determine the import function</h3>

From the table, we can see that the values of the import is twice the number of months

This is represented as:

y = 2x

Rewrite as a function

f(x) = 2x

Hence, the function that represents the number of imports is f(x) = 2x

<h3>How to determine the export function</h3>

From the table, we can see that the values of the export is two more than the number of months

This is represented as:

y = 2 + x

Rewrite as a function

f(x) = 2 + x

Hence, the function that represents the number of exports is f(x) = 2 + x

Read more about linear functions at:

brainly.com/question/15602982

7 0

3 years ago

Select the two values of x that are roots of this equation. 2x^2-11x+15=0

zaharov [31]

Hey there! :)

Answer:

x = 5/2 and 3.

Step-by-step explanation:

Factor the equation. Find numbers that will sum up to -11 involving the coefficient of 2, and that multiply into 15.

2x² - 11x + 15 = 0

(2x - 5)(x - 3) = 0

Use the Zero Product Property to solve for the roots of this equation:

2x - 5 = 0

2x = 5

x = 5/2

----------

x - 3 = 0

x = 3.

Therefore, the two values of x that are roots of this equation are:

x = 5/2 and 3.

4 0

3 years ago

Read 2 more answers

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

7 0

3 years ago