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shutvik [7]
3 years ago
7

Ken paid for $12 for two magazines. The cost of each magazine was a multiple of 3. What is Mare the possible prices of the magaz

ines?
Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:

So the possibilities are

$12 and $ 0    ,    $9 and $ 3      , $6 and $6

Step-by-step explanation:

Given:

Total Magazines = 2

Price = $ 12

To Find:

Possible Prices of magazines = ?

Solution:

As it is given that Prices of magazines is multiples of 3

So

Multiples of 3 up till 12 are  

0, 3 , 6 , 9 , 12

Now

Total Price of magazine is $12

Now The possible prices of the magazines are

First Possibility:

If price of first magazine is $12 then second would be $0 (free)

First possible price $12 and $0

Second Possibility:

If price of first magazine is $9 then second would be $3

Second possible price $3 and $9

Third Possibility:

If price of first magazine is $6 then second would be $6

Third possible price $6 and $6

So the possibilities are

$12 and $ 0    ,    $9 and $ 3      , $6 and $6

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Answer:

it might go like A= 12 B= 0 C = -6

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Evaluate the function: f(-x)=x^2+9x-6
astraxan [27]

Answer:

f(-x) = x² - 9x - 6

General Formulas and Concepts:
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

f(x) = x² + 9x - 6

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function f(x)]:                                                                       f(-x) = (-x)² + 9(-x) - 6
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2 years ago
A farmer had a plot of land measuring 15 yd. by 11 yd. Thefarmer put up a fence,leaving a margin of 2 yd. wide all round it. (a)
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The answer would be 850.85
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There has been a great deal of controversy over the last several years regarding what types of surveillance are appropriate to p
alexira [117]

Answer:

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

Step-by-step explanation:

There are 1000 future terrorists in a population of 300,000,000. So the probability that a randomly selected person in this population is a terrorist is:

P = \frac{1,000}{300,000,000} = 0.000003 = 0.0003%

So, we have these following probabilities:

A 99.9997% probability that a randomly chosen person is not a terrorist.

A 0.0003% probability that a randomly chosen person is a terrorist.

A 98% probability that a future terrorist is correctly identified

A 99.9% chance of correctly identifying someone who is not a future terrorist. This also means that there is a 0.01% probability of someone who is not a terrorist being identified as one.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Here we have:

What is the probability that the person is a terrorist, given that she was identified as a terrorist.

P(B) is the probability that the person is a terrorist. So P(B) = 0.000003

P(A/B) is the probability that the person was identified as a terrorist, given that she is a terrorist. The problem states that the system has a 98% chance of correctly identifying a future terrorist, so P(A/B) = 0.98

P(A) is the probability of a person being a identified as a terrorist. So

P(A) = P_{1} + P_{2}

P_{1} is the probability that a person is a terrorist and was identified as one. So:

P_{1} = 0.000003*0.98 = 0.00000294

P_{1} is the probability that a person is not a terrorist and, but was identified as one. So:

P_{2} = 0.999997*0.0001 = 0.0000999997

So

P(A) = P_{1} + P_{2} = 0.00000294 + 0.0000999997 = 0.000103

The answer is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.000003*0.98}{0.000103} = 0.028544

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

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