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almond37 [142]
3 years ago
10

Can someone please Find the Y, the equation to find it is in the top middle. I need the Y found for all 5 X points

Mathematics
1 answer:
katovenus [111]3 years ago
4 0
Hope this helps you! :)

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Oscar has a piece of pie would that is 9‘ x 9‘ explain how we can divided into two smaller pieces of plywood would the area of t
Dimas [21]

Answer:

1. with the aid of a saw

2.No

Step-by-step explanation:

A. The  9‘ x 9‘ can be divided into two with the aid of a saw .

we have to take into account the area of the shape wic 9'x9'. and then saw the piece at the middle.

b.there are two sides to the second answer

1. the area of the smaller pieces will be smaller than the area of the larger piece

2. when the smaller pieces are placed side by side aain , tere area combined together will be the same as the original piece

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3 years ago
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8 cm What is the area, in square centimeters, of the circle?​
Kobotan [32]

Answer:

50.265

Step-by-step explanation:

6 0
3 years ago
A survey of couples in a city found the following probabilities:
liraira [26]

Answer

(a) 0.94

(b)0.06

Step-by-step explanation:

P(husband is employed) = P(H) = 0.85

P(wife is employed) = P(W) = 0.59

P(both are employed) = P(H∩W) = 0.50

(a) At least one of them is employed

= P(H∪W)

= P(H) + P(W) - P(H∩W)

=0.85 + 0.59 - 0.50

=0.94

(b) Neither is employed,

=1 - P(H∪W)

= 1-0.94

=0.06

8 0
3 years ago
Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ<2π. secant StartFraction 5 theta Over 4 En
qaws [65]

Answer:  4π/15, 4π/3 and 28π/15 (in radians)

Step-by-step explanation:

sec 5\theta/4 =2

Recall that sec \theta = 1/cos \theta

1/cos (5\theta/4) =2

cos (5\theta/4) =1/2

Cos^{-1} \frac{1}{2} = 5\theta/4

This implies that

\mp60+360n=5\theta/4

\theta=4/5(\mp60+360n)= \mp48+288n

When  n=0, \theta=48

When  n=1, \theta=240, 336

Therefore the values of \theta between 0 and 2π are 48, 240 and 336. (All in degrees)

48 degrees= 4π/15 rad

240 degrees =4π/3 rad

336 degrees = 28π/15 rad

5 0
3 years ago
A coordinate plane is placed over an empty lot. You and a friend stand back-to-back at the origin. You face the positive y-axis
Sunny_sXe [5.5K]
The graph of the positions is attached.

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4 years ago
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