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2 years ago

Finding domain f(x)=3x+1/x-5

1 answer:

4 0

The function is undefinded if the denominator, x-5, equals 0.
So $x-5 \neq 0 \\ 
x \neq 5$ .
The domain is $x \neq 5$ .
In interval notation, this is (-infinity, 5) u (5, infinity).

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What are two expressions that are equivalent to 6(5j + 2 + j)?

ziro4ka [17]

Answer:

1. 30j+12+6j

2. 36j+12

3. 6(6j+2)

Step-by-step explanation:

1. You just multiply so... 6x5j ... 6x2 ... 6xj

2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12

3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)

5 0

3 years ago

Please help! which of the following is closest to the mean of the data set shown?

Allisa [31]

Answer:

3 is the answer

Step-by-step explanation:

add all 6 numbers up then divide by 6

5 0

2 years ago

Read 2 more answers

Two quantities are related, as shown in the table:

kompoz [17]

is Y= 3 over 2 x because y add 3 and x add 2

3 0

2 years ago

In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

8 0

3 years ago

The mode of 1.5, 1.6, 2, 2, 3.4, 5.6, 5.9 is 3.14. True False

inessss [21]

The answer is FALSE, the mode in a sequence is the number that appears most often; the mode is 2.

6 0

2 years ago