1. 0.5=5/10
5/10*100=50%
2. 7.24 =724/100
724/100*100=724%
3. 1.86=186/100
186/100*100=186%
Answer:
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True because 6 multiplied by 3 is 18. Therefore, when you divide 18 by 6 the anwser will be 3.
It may help you to consider the standard normal curve. If the mean here is 70%, then 0.5 of the area under this curve. In other words, half the students received a grade > 70%. That would be 100 students.
Note that 84 is 2 std dev above the mean.
Recall the Empirical Rule: 95% of scores lie within 2 std. dev of the mean.
Measuring from the mean, that would be 47.5% above the mean and 47.5% below the mean. The area to the right of the mean is 0.5. Subtract 0.475 from that to obtain the fraction of students who rec'd a grade greater than 2 std dev from the mean: It's 0.025.
Then the # of students who rec'd a grade greater than 84% would be
0.025(200 students) = 5 students.
<span>it depends on what type of format is used.</span>