Answer:
2257m3
Step-by-step explanation:
50x25x2=2500
2500-243=2257
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
![r= [(\frac{A}{2500}) ^\frac{1}{2} -1]](https://tex.z-dn.net/?f=r%3D%20%5B%28%5Cfrac%7BA%7D%7B2500%7D%29%20%5E%5Cfrac%7B1%7D%7B2%7D%20-1%5D)
Step-by-step explanation:
Given data
Principal = $2500
time t= 2 years
Required
the rate r
Given the expression for the balance 2500(1+r)^2
Hence
we can make r subject of formula
![r= [(\frac{A}{P}) ^\frac{1}{t} -1]](https://tex.z-dn.net/?f=r%3D%20%5B%28%5Cfrac%7BA%7D%7BP%7D%29%20%5E%5Cfrac%7B1%7D%7Bt%7D%20-1%5D)
Hence, for any value of A, we can find the rate using the expression above
Integers are a whole number that isn’t a fraction ,examples: 0,1,2,3 non examples: 3.14, 1 1/2(this is a fraction)
