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kipiarov [429]
3 years ago
15

What is the scientific notation of 0.00277

Mathematics
1 answer:
pentagon [3]3 years ago
6 0
The answer is 2.77 • 10^3
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Help me I need help with this factorization of 630?
nignag [31]

Answer:

The prime factors are: 2 x 3 x 3 x 5 x 7

or also written as { 2, 3, 3, 5, 7 }

Written in exponential form: 2 x 3 × 3 x 5 ×1  x 7×1

6 0
3 years ago
(this is 6 grade math) PLEASE HELP<br>​
pochemuha
Answer
11a + 4a= 15a
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I think these are the answers please don’t get mad if they are not hope I help :)
8 0
3 years ago
Read 2 more answers
A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s
mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, \theta=25°

Initial speed is, u=15\ m/s

Time of flight is, t=3.0\ s

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = -h (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, g=-9.8\ m/s^2

Now, using the following equation of motion;

-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, v_y=0\ m/s

Now, using the following equation of motion, we have:

v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m

Therefore, the maximum height of the brick is 2.05 m.

5 0
3 years ago
What is 9x^2-18x-7÷(3x+1)
Phantasy [73]
81x - 126x ÷ 3x + 1
45x / 3x + 1
15x / x + 1
6 0
3 years ago
I need the answer if you know write with explination if you don't know don't answer ​
yarga [219]

Answer:

ABD ≅ ACD and PQS ≅ PRS

Step-by-step explanation:

For ABD ≅ ACD;

AB = AC = 3.5

BD = CD = 2.5

AD ≅ AD by reflexive

Since all 3 sides are congruent, SSS can be used

For PQS ≅ PRS

PQ≅PR by given

QS≅RS by given

PS≅PS by reflexive property

Since all 3 sides are congruent, SSS can be used and they are congruent

8 0
3 years ago
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