Answer:
Step-by-step explanation:
Your checkmarks are in the right places. So the answers are correct that you have chosen.
Hello,
g(x)=x²+3
f(x)=2/x
so f(g(x))=f(x²+3)=2/(x²+3)
Explainations:
f(y)=2/y
f(4y)=2/(4y)
f(x²)=2/x²
f(x²+3)=2/(x²+3)
For you to make an equation a quadratic equation, you need everything to be on one side, so you add one to both sides.
<span>2x^2 + 3x + 0=0 </span>
<span>a=2, b=3, c=0 </span>
<span>b^2-4ac (In the next step just plug in your variables) </span>
<span>3^2 - 4(2)(0) </span>
<span>9 - 8(0) </span>
<span>9 - 0 </span>
<span>Your answer=9</span>
Hey there! :)
Answer:
Third option. x = 2, and x = 4.
Step-by-step explanation:
Find the zeros of this quadratic equation by factoring:
f(x) = x² - 6x + 8
Becomes:
f(x) = (x - 4)(x - 2)
Set each factor equal to 0 to solve for the roots;
x - 4 = 0
x = 4
x - 2 = 0
x = 2
Therefore, the zeros of this equation are at x = 2, and x = 4.
