1st it: g(2)=3(2)=6 || 2nd it: g^2(2)=3(6)=18 || 3rd it: g^3(2)=3(18)=54
Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
9 - 2(7 - 8)
9 - 2(-1)
9 - (-2)
11
Answer:
<u>The correct answer is C. 4 -6</u>
Step-by-step explanation:
Let's solve the operation given, this way:
(7 - 11/) + (-3 + 5/)
7 - 11 - 3 + 5=
12 - 14 = - 2
<u>After resolving the parenthesis, adding and subtracting the result of thhe operation is - 2</u>
<u>The correct answer is C. 4 -6</u>
Answer:
i think is Quadratic function
