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weeeeeb [17]
2 years ago
13

The widths of two similar rectangles have a ratio of 2:6 . The area of the smaller rectangle is 12 ft2. What is the area of the

larger rectangle? Enter your answer in the box.
Mathematics
1 answer:
Korolek [52]2 years ago
8 0

Answer:

The area of the larger rectangle is 108\ ft^{2}

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its areas is equal to the scale factor  squared

and the ratio of its corresponding sides is equal to the scale factor

Let

z-----> the scale factor

x-----> the area of small rectangle

y-----> the area of larger rectangle

so

z^{2} =\frac{x}{y}

we have

z=2/6

x=12\ ft^{2}

substitute  and solve for y

(2/6)^{2} =\frac{12}{y}

y=12/(4/36)=108\ ft^{2}

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hope it helps

stay safe healthy and happy.

8 0
2 years ago
Plsss help me with this, Brainlist!!!
irina [24]

Answer:

1. -3

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4 0
3 years ago
A bit confused on what to do. Can someone help?
Allisa [31]

Answer: the answer is on a calculator

Step-by-step explanation:

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4 0
2 years ago
A museum has a model of an Egyptian pyramid. It has a rectangular base that is 10 feet by 8 feet, with a height of 12 feet.
FrozenT [24]

Answer: 320ft^3

Step-by-step explanation:

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10x8x12/3 = 320 ft^3

7 0
3 years ago
If the legs of an isosceles right triangle have a length of 15 StartRoot 2 EndRoot ft, what is the length of the hypotenuse?
lorasvet [3.4K]

Answer:

30 ft

Step-by-step explanation:

a² + b² = c²

(15sqrt(2))² + (15sqrt(2))² = c²

225 * 2 + 225 * 2 = c²

c² = 900

c = sqrt(900)

c = 30

Answer: 30 ft

4 0
2 years ago
Read 2 more answers
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