The exercise is about filling in the gaps and is related to the History of the ARPANET.
<h3>
What is the History of the ARPANET?</h3>
From the text:
In 1972, earlier designers built the <u>ARPANET </u>connecting major universities. They broke communication into smaller chunks, or <u>packets </u>and sent them on a first-come, first-serve basis. The limit to the number of bytes of data that can be moved is called line capacity, or <u>bandwidth</u>.
When a network is met its capacity the user experiences <u>unwanted pauses</u>. When the network is "slowing down", what is happening is users are waiting for their packet to leave the <u>queue</u>.
To make the queues smaller, developers created <u>mixed </u>packets to move <u>simultaneously</u>.
Learn more about the ARPANET at:
brainly.com/question/16433876
The correct answer is C. Customer spreadsheet
Answer:
A keyboard, mouse, and microphone all are examples of <u>peripheral devices.</u>
Explanation:
hope this helps
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

⇒ t = 8.7*10⁻⁴ sec.