Answer:
def odd_even(N):
for number in range(0, N+1):
if number % 2 == 0:
print(str(number) + " is even")
elif number % 2 == 1:
print(str(number) +" is odd")
odd_even(5)
Explanation:
- Create a method called odd_even that takes one parameter, N
- Initialize a for loop that iterates through 0 to N
Inside the loop, check if module of the number with respect to 2 is equal to 0. If yes, print it as even number. If module of the number with respect to 2 is equal to 1, print it as odd number
Call the method
Phishing is an ability of fraudulently obtaining personal info.
synonyms: Fraud and scam
Answer:
Four times traveling 40,12345 mts
Explanation:
We can express this as a sum as follows

The first term is the dropping part and the second is the upward motion. this sums up to 40,12345 m after bouncing four times. As a program we could write using the while loop.
distance=0;
i:=0;
while distance<40 do
i:=i+1;
distance:=distance+ 
end while;
Here the answer is in i and the closest distance traveled after reaching 40 is in the variable distance.
mcvaefn<AMsdnmklmgkdmflavm
The answer is No
Answer:
This should be done in a PowerPoint presentation and word processor like MS PowerPoint and MS Word (if I understood your question correctly)