Answer:
259.60-300=-40.4
Step-by-step explanation:
x - 2 + x + 4 + x - 2 + 4 - 4 = x + 3 + x + 4 + x + 5
4x + 4 = 3x + 12
4x - 3x = 12 - 4
x = 8
n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
SA=4pir^2
SA=4pi13^2
SA=4pi169
SA=676pi ft^2
Answer:
40
Step-by-step explanation:
LxW=A
So 4x10=40
Hope this helps
