How wide is a poster that has a length of 9/2 feet and area of 45/4 square feet?

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

Area = length × width
45/4 = 9/2 × width
width = (45/4) ÷ (9/2)
= 5/2 feet

defon3 years ago

7 0

A=LW, area equals the product of the length times the width, so we can say:

W=A/L, we are told that A=45/4 and L=9/2 so:

W=(45/4)/(9/2) ft

W=(45/4)*(2/9)=90/36 ft

W=5/2 ft

W=2.5 ft.

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