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Andru [333]
3 years ago
7

How wide is a poster that has a length of 9/2 feet and area of 45/4 square feet?

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0
Area = length × width
45/4 = 9/2 × width
width = (45/4) ÷ (9/2)
= 5/2 feet
defon3 years ago
7 0
A=LW, area equals the product of the length times the width, so we can say:

W=A/L, we are told that A=45/4 and L=9/2 so:

W=(45/4)/(9/2) ft

W=(45/4)*(2/9)=90/36 ft

W=5/2 ft

W=2.5 ft.
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Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

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Step-by-step explanation:

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A researcher would like to estimate p, the proportion of U.S. adults who support recognizing civil unions between gay or lesbian
Minchanka [31]

Answer:

Question 1:

(b) 4,445

Question 2:

(c) 2.1%

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Question 1:

We have no previous estimate for the population proportion, so we use \pi = 0.5.

The sample size is n for which M = 0.015. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.015\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.015}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.015})^2

n = 4268

Samples above this value should be used, and the smaller sample above this value is of 4445, so the answer is given by option b.

Question 2:

Now we find M for which n = 2222.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.5*0.5}{2222}}

M = 0.021

So 2.1%, and the correct answer is given by option c.

3 0
2 years ago
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