Answer:
165km
Step-by-step explanation:
If Gina leaves now and drives at 66km/h she will reach Alton just in time for her appointment
Now:
Distance=Speed X Time
D=66 X t=66t.....(I)
If she leaves in 40 minutes,and she must get there at the same time, her new drive time will be:
t hours - 40 minutes
=(t-40/60)hours=( t-2/3) hours
Her Distance this time
D=90(t-2/3)=90t-60.....(ii)
Since the distance to Alton does not change, we equate (I) and (ii)
66t=90t-60
60=90t-66t
60=24t
t=2.5 hours
From equation (I)
Distance=66t=66X2.5=165km
Distance to Alton is 165km.
Answer:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Step-by-step explanation:
The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.
The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.
The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.
The answer is:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Answer:
{2, 6, 14}
Step-by-step explanation:
Using f(x) = 4x + 6 with a domain of {-1, 0, 2 }, find the range.
To get the range, we will substitute the values of the domain into the given function as shown;
when x = -1
f(-1) = 4(-1)+6
f(-1) = -4+6
f(-1) = 2
when x = 0
f(0) = 4(0)+6
f(0) = 0+6
f(0) = 6
when x = 2
f(2) = 4(2)+6
f(2) = 8+6
f(2) = 14
Hence the required range are {2, 6, 14}
Answer:
the number that you divide by is called the dividend and the number which the dividend is being divided by is the divisor.
