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kkurt [141]
4 years ago
9

Write the number in to other forms: 0.326

Mathematics
2 answers:
Masja [62]4 years ago
7 0
362/1000 = 181/500
I only know that one, sorry
Free_Kalibri [48]4 years ago
7 0
I think it also might be 32.6 percent

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Im going to give 15 points for this question please answer it
Gnom [1K]
I know, you have to divide 90 by what ever the length is, then you have to figure out where the points are. So it should be.... D!!!
8 0
4 years ago
Find the 50th term of the following<br> arithmetic sequence 5, 9, 13, 17?
yarga [219]

Answer:

201

Step-by-step explanation:

First you need to know the position to term rule and to find this you use a formula which is:

tn = an + b

Where tn is the term number,  a is the difference between the other terms.

So the tposition to term rule here is 4n+1.

Then we substitute n for the value 50 making it 4(50) + 1 = 201.

201 is the 50th term

6 0
3 years ago
What’s the answer? And how do I solve it ?
OLga [1]

Answer:5 2/3


Step-by-step explanation:

add 2 and 3

then you add 1/3 and 1/3

2+3=5

1/3 + 1/3=2/3

5 2/3

8 0
3 years ago
Which inequalities are true? Check all that apply.
garri49 [273]

Answer: A , B, C, E

Step-by-step explanation:√4 = 2√5 = 2.24√5.5 = 2.36√6 = 2.45√8 = 2.83√9 = 3

A)√5 < 2.3<√62.24 < 2.3 < 2.45 True

B)√5 < 2.4<√62.24 < 2.4 < 2.45 True

C)√4 < √5 < √5.52 < 2.24 < 2.36 True

D)√8 < 3 < √92.83 < 3 < 3 False

E)√8 < 2.9 < √92.83 < 2.9 < 3 True

F)√4 < 4.5 < √52 < 4.5 < 2.24 False

4 0
3 years ago
1. A computer technician charges a flat fee of $35 to repair a computer in addition to an hourly rate of $22.50. The technician
Misha Larkins [42]

1. Multiply the hourly rate by the number of hours worked ( 22.5h) add that to the flat fee ( 22.5h +35) and that needs to be equal to or greater than what he expects to make:

A. 22.5h + 35 ≥ 215 , with a solution of h ≥ 8

2. Same method as number 1:

C. $3 + 1.80m ≤ $25

3. Each fraction would need 1 negative sign and have the same numerator and denominator, so the answer would be B.6/-7

8 0
3 years ago
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