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bixtya [17]
4 years ago
8

Rewrite the formula for the circumference of a circle C=2xpix r in terms of its diameter d. Show your work.

Mathematics
2 answers:
ozzi4 years ago
7 0
Hi there!

The answer is
circumference \:  = d\pi
In this formula d represents the diameter.

We know that 2 times the radius equals the diameter, hence
2r = d

Therefore we can replace the 2r in the original formula by d, and then we get the following:
circumference = 2\pi \: r = 2r\pi = d\pi
Keith_Richards [23]4 years ago
3 0
Diameter = 2·radius

С = 2·π·r   ⇒    С = π·d   
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EMERGENCY! <br><br> How many cubes with side lengths of 1/2 cm does it take to fill the prism?
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Answer:

  24 cubes

Step-by-step explanation:

You can figure this a couple of ways.

I usually find it easiest to figure in terms of the number of cubes each dimension represents. The vertical dimension (3/2 cm) is the length of 3 cubes; the front-back dimension (2 cm) is the length of 4 cubes, and the width (1 cm) is the length of 2 cubes.

The total number of cubes required is the product of the dimensions in cube-lengths: 3×4×2 = 24 cubes.

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Another way to figure this is to compute the prism volume in the given dimensions (cm³) and the cube volume in the same dimensions, then find the number of cube volumes in the prism volume.

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Then the number of cubes that will fit in the prism is ...

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6 0
4 years ago
What do you notice about the table inputs for the graph of √x?
Airida [17]

Answer:

See below

Step-by-step explanation:

When we talk about the function f(x)=\sqrt{x}, the domain and codomain are generally defaulted to be subsets of the Real set. Once $f:[0,\infty)\to [0,\infty)$ and  $f\subseteq [0,\infty)\times [0,\infty)$ such that $(x,y_1)\in f\wedge(x,y_2)\in f \Rightarrow y_1=y_2$  for $f(x)=\sqrt x$. Therefore,

\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]

\[x \mapsto \sqrt{x}\]

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Step-by-step explanation:

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3 years ago
Solve: 3(2x - 5) = 6x - 15
Levart [38]
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subtract 6x from  both sides:

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Answer D

hope this helps!

3 0
3 years ago
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