**80 Points** Please Answer!
2 answers:
Hey there! So to find these answer to your questions, you must find the dominant allele a recessive allele
To do that you add the P and the q to equal 1
Then Multiply it times to
Now each will equal
A.2.6%
B.84%
C.26.9%
So let's make p = dominant allele and q = recessive allele p+q = 1, and (p+q)^2 = 1^2 thus p^2 + 2pq + q^2 = 1, where p^2 = homozygous dominant, 2pq = heterozygous, and q^2 = homozygous recessive So if p = .84, then q = 1-.84 = .16 a) recessive phenotype = q^2 = (.16)^2 = .0256 = 2.6% b) dominant allele = p = .84 = 84% c) heterozygous genotype = 2pq = 2(.84)(.16) = .269 = 26.9%
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