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BaLLatris [955]
4 years ago
12

A shipping company uses an inclined conveyor belt to load or unload packages. The dock is 15 feet above ground. The base of the

conveyor belt is 40 feet from the dock. What is the length the conveyor belt?
Mathematics
1 answer:
alexgriva [62]4 years ago
7 0
Hey there! :D

Think of this like a triangle. The dock is 15 feet above ground. It is the side of the triangle. The line connecting the bottom of the dock to the base of the conveyor belt is 40 feet. This is like the base. 

The conveyor belt itself is at a diagonal, and should be the hypotenuse. 

Use the Pythagorean theorem. 

a^2+b^2=c^2

15^2+40^2= c^2 

225+1,600= c^2

Add the values together. 

1,825= c^2

Find the square root of 1,825. 

c= 42.7 (rounded to the nearest tenth) 

The conveyor belt is 42.7 feet long.

I hope this helps!
~kaikers


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3 years ago
Select the correct answer.
EleoNora [17]

Answer:

Option (B)

Step-by-step explanation:

There are two lines on the graph representing the system of equations.

First line passes through two points (-3, 1) and (-2, 3).

Slope of the line = \frac{y_2-y_1}{x_2-x_1}

                           = \frac{3-1}{-2+3}

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Equation of the line passing through (x', y') and slope = m is,

y - y' = m(x - x')

Equation of the line passing through (-3, 1) and slope = 2 will be,

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Let the equation of this line is,

y = mx + b

Slope 'm' = \frac{y_2-y_1}{x_2-x_1}

               = \frac{4-1}{-1-0}

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Here 'b' = 1

Therefore, equation of the line will be,

y = -3x + 1 ---------(2)

From equation (1) and (2),

2x + 7 = -3x + 1

5x = -6

x = -\frac{6}{5}

x = -1\frac{1}{5}

From equation (1),

y = 2x + 7

y = -\frac{12}{5}+7

  = \frac{-12+35}{5}

  = \frac{23}{5}

  = 4\frac{3}{5}

Therefore, exact solution of the system of equations is (-1\frac{1}{5},4\frac{3}{5}).

Option (B) will be the answer.

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4 years ago
Question 7 (1 point)<br> Solve: 8x = 56
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8x = 56

To solve this, we must simplify. To do this, we must divide each side by 8. This, in term, will give us the value of x.

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5 0
3 years ago
Which system of equations below has infinitely many solutions? y = –3x 4 and y = –3x – 4 y = –3x 4 and 3y = –9x 12 y = –3x 4 and
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the equations y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions. option B is correct.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Condition for the parallel lines.

L1,  ax + bx + c = 0

L2, dx + ey + f = 0

If \rm \dfrac{a}{d} = \dfrac{b}{e} = \dfrac{c}{f} then lines have infinitely many solutions.

<h3>Which system of equations below has infinitely many solutions?</h3>

y = –3x + 4 and 3y = –9x + 12

On comparing we have

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d = -9 , e = 3, and f = 12

Then their ratio will be

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Hence  y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions.

Thus the option B is correct.

More about the linear system link is given below.

brainly.com/question/20379472

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Can someone help me with this question on Prodigy? ​
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Answer:

  8 +(3/8)√53 in² ≈ 10.73 in²

Step-by-step explanation:

Given the net of a triangular pyramid with some of the dimensions filled in, you want to find the total surface area.

<h3>Triangle base</h3>

The triangle bases identified by dashed lines will have a length equal to the hypotenuse of the right triangles with legs shown as solid lines. The legs of each of those right triangles are ...

  a = (3 in)/2 = 1.5 in

  b = 2 in . . . . . . shown as the altitude of the triangle

Then the hypotenuse is found using the Pythagorean theorem:

  c² = a² +b²

  c² = 1.5² +2² = 2.25 +4 = 6.25

  c = √6.25 = 2.5

The dashed lines are 2.5 inches long.

<h3>Triangle altitude</h3>

The altitude from the solid horizontal line to the vertex at the bottom of the figure can be found using the fact that all of the outside edge lengths of the net are the same length. That edge length is found as the length of the hypotenuse of the right triangles in the left- and right-sides of the upper portion of the net. Each of those has a leg that is (2.5 in)/2 = 1.25 in and a leg marked as 2 in.

  c² = a² +b²

  c² = 1.25² +2² = 1.5625 +4 = 5.5625

  c = (√89)/4 ≈ 2.358 . . . in

The unmarked altitude of the bottom triangle is then ...

  b² = c² -a²

  b² = 89/16 -1.5² = 53/16

  b = (√53)/4 ≈ 1.820 . . . in

<h3>Surface area</h3>

The surface area of the figure is the sum of the areas of the four triangles that make up the net. Each triangle has an area given by the formula ...

  A = 1/2bh

The left and right triangles have b=2.5, h=2, so they each have an area of ...

  A = 1/2(2.5)(2) = 2.5 . . . . in²

The center triangle has dimensions of b=3, h=2, so an area of ...

  A = 1/2(3)(2) = 3 . . . . in²

The bottom triangle has dimensions of b=3, h=(√53)/4, so an area of ...

  A = 1/2(3)(√53/4) = (3/8)√53 ≈ 2.730 . . . . in²

The total surface area is the sum of the areas of these triangles, so is ...

  A = 2.5 in² +2.5 in² +3 in² +2.73 in² = 10.73 in²

The surface area of the triangular pyramid is (64+3√53)/8 ≈ 10.73 in².

__

<em>Additional comment</em>

Often we work with pyramids that are rotationally symmetrical about a vertical line through the peak. This one is not. The altitude of the bottom triangle in the net is less than the altitude of the other triangles. This short face of the pyramid will tend to be more vertical than the other two lateral faces.

4 0
1 year ago
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