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2 years ago

Please help!!!!im struggling!!!!!!!!!

Mathematics

1 answer:

Kitty [74]2 years ago

6 0

Answer:

the answer is the second one

Step-by-step explanation:

have a great day :)

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Y=4 horizontal yes or no

Serga [27]

Answer:

yes

Step-by-step explanation:

The equation of a horizontal line parallel to the x-axis is

y = c

where c is the value of the y- coordinates the line passes through

y = 4 is a horizontal line passing through all points with a y- coordinate of 4

4 0

3 years ago

Is this right

pychu [463]

Answer:

360 = x+123+ 90

x = 147

Step-by-step explanation:

The three angles form a circle which is 360 degrees

360 = x+123+ 90

Subtract 123 and 90 from each side

360 -123 - 90 = x

147 = x

6 0

3 years ago

Read 2 more answers

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

Read 2 more answers

What is the solution?<br><br> 2x+y=-3

OLEGan [10]

2x+y+3=0
...................

5 0

2 years ago

Compare the surface area-to-volume ratios of the moon and mars. express your answer using two significant figures.

antoniya [11.8K]

we know that

For a spherical planet of radius r, the volume V and the surface area SA is equal to

$V=\frac{4}{3} *\pi *r^{3} \\ \\ SA=4*\pi *r^{2}$

The
ratio of these two quantities may be written as

$SAV =\frac{(4*\pi*r^{2})}{(\frac{4}{3}*\pi*r^{3})} \\ \\ SAV =\frac{3}{r}$

we know

$rMoon=1,738Km\\ rMars=3,397 Km$

$\frac{SAV Moon}{SAV Mars} =\frac{3}{rMoon} *\frac{rMars}{3} \\ \\ \frac{SAV Moon}{SAV Mars} =\frac{rMars}{rMoon} \\ \\ \frac{SAV Moon}{SAV Mars} =\frac{3,397}{1,738} \\ \\ \frac{SAV Moon}{SAV Mars} =1.9545$

therefore

the answer is

$1.9$

5 0

3 years ago

Read 2 more answers