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Serga [27]
3 years ago
11

Please help!!!!im struggling!!!!!!!!!

Mathematics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

the answer is the second one

Step-by-step explanation:

have a great day :)

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Quadrilateral ABCD has diagonals AC and BD. Which information is not sufficient to prove ABCD is a parallelogram
lianna [129]
Because you are missing one whole side of the triangle
6 0
3 years ago
Jessie painted a rectangular wall that measured 7 yards by 3 yards.
Lunna [17]

Answer:

Im gonna have to say 21 yd^2.

Step-by-step explanation:

L*W=A^2 so... 7*3=21

7 0
3 years ago
Read 2 more answers
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
From the observation deck of a skyscraper, Isabella measures a 67
Ivenika [448]

Answer:

1941.2  feet

Step-by-step explanation:

\frac{824}{tan\left(23\right)}

8 0
3 years ago
The coordinates of the vertices of triangle ABC are A(-1,3), B(1,2) and C(-3,-1).
Romashka [77]
In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC  and AB have any  negative reciprocals.Lets find the slopes . 
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1

Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle 
5 0
3 years ago
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