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2 years ago

11

Please help!!!!im struggling!!!!!!!!!

1 answer:

Kitty [74]2 years ago

6 0

Answer:

the answer is the second one

Step-by-step explanation:

have a great day :)

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Mark's age, x , is 6 times his age 2 years ago. which equation represents the statement?

AlekseyPX

Answer:

x = 6(x - 2)

Step-by-step explanation:

His age now is x.

His age 2 years ago was x - 2.

x = 6(x - 2)

5 0

2 years ago

Find the standard form of the equation of the ellipse with the given characteristics. Vertices: (4, 0), (4, 14); endpoints of th

saul85 [17]

Answer:

The standard form of the ellipse is $\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1$ .

Step-by-step explanation:

The major axis of the ellipse is located in the y axis, whereas the minor axis is in the x axis. The center of the ellipse is the midpoint of the line segment between vertices, this is:

$(h, k) =\frac{1}{2}\cdot V_{1} (x,y) + \frac{1}{2}\cdot V_{2} (x,y)$ (1)

If we know that $V_{1} (x,y) = (4,0)$ and $V_{2}(x,y) = (4, 14)$ , then the coordinates of the center are, respectively:

$(h,k) = \frac{1}{2}\cdot (4, 0) + \frac{1}{2}\cdot (4,14)$

$(h,k) = (2,0) + (2, 7)$

$(h, k) = (4, 7)$

The length of each semiaxis is, respectively:

$a = \sqrt{(1 - 4)^{2}+(7-7)^{2}}$

$a = 3$

$b = \sqrt{(4-4)^{2}+(0-7)^{2}}$

$b = 7$

The standard equation of the ellipse is described by the following formula:

$\frac{(x-h)^{2}}{a^{2}}+ \frac{(y-k)^{2}}{b^{2}} = 1$

Where:

$h$ , $k$ - Coordinates of the center of the ellipse.

$a$ , $b$ - Length of the orthogonal semiaxes.

If we know that $h = 4$ , $k = 7$ , $a = 3$ and $b = 7$ , then the standard form of the ellipse is:

$\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1$

4 0

3 years ago

PLZ HURRY i need this for test if you have the answers for all questions plz put the test is for plato algebra A1 unit3 post tes

elena-14-01-66 [18.8K]

Explanation is in the file

tinyurl.com/wpazsebu

7 0

3 years ago

What model represents 2x0.9

natima [27]

Answer: the bottom one

Step-by-step explanation:

3 0

3 years ago

Solve for y 2x+y-3z=5

Elza [17]

Answer:

<h3>A. y=-2x+3z+25</h3>

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

<u>To solve:</u>

The value of y.

$\Longrightarrow: \sf{\sqrt{2x+y-3z}=5}$

<h3>2x+y-3z=25</h3>

<u>First, you have to subtract by 2x-3z from both sides.</u>

$\Longrightarrow: \sf{2x+y-3z-\left(2x-3z\right)=25-\left(2x-3z\right)}}$

<u>Solve.</u>

$\Longrightarrow: \boxed{\sf{y=25-2x+3z}}}$

<u>Therefore, the correct answer is "A. y=-2x+3z+25".</u>

I hope this helps, let me know if you have any questions.

4 0

2 years ago

Read 2 more answers