Answer:
The speed of the cyclist is 10 miles per hour .
Step-by-step explanation:
Given as :
The distance cover by cyclist =
= 20 miles
The distance cover by biker =
= 6 miles
The speed of biker =
= s mph
The speed of cyclist =
= 7 + s mph
The time taken by both cyclist and biker = t hour
Now. Distance = Speed × Time
So,
=
× t
Or, 20 = s × t
Or, t =
.....1
And ,
=
× t
or, 6 = s t
Or, t =
....2
From Eq 1 and 2
I.e
=
Or, 20 s = 6 ( 7 + s )
Or, 20 s - 6 s = 42
Or, 14 s = 42
∴ s = 
I,e s = 3 miles per hour
So, The speed of biker =
= s = 3 miles per hour
And The speed of cyclist =
= 7 + s = 7 + 3= 10 miles per hour
Hence The speed of the cyclist is 10 miles per hour . Answer
Answer:
The answer is x - 13y
Step-by-step explanation:
Answer:
-5 and -4
Step-by-step explanation:
It is far easier just to solve the equation than to determine appropriate integer bounds on the solution.
In the attachment, we show a couple of initial trials at solutions. The nearness of y=5 to being correct suggests that the next higher integer may be helpful, too. It is.
We find -4 and -5 to bracket the solution.
_____
The actual solution is (3.4 -1.3)/-0.5 = -4.2.
Two<span> trains </span>leave different<span> cities heading toward each </span>other<span> at </span>different<span> speeds. ... At the </span>same time<span>Train B, </span>traveling 60 mph<span>, leaves Eastford heading toward Westford. ... Since an equation remains true as </span>long<span> as we perform the </span>same<span> operation ... that the train's rate is 40 </span>mph<span>, which means it </span>will travel<span> 40 </span>miles<span> in </span>one<span> hour.</span>
The practical domain is all real numbers from 4 to 9, inclusive.
The practical range is all real numbers from 49.6 to 111.6, inclusive.
These are the correct options.
Explanation:
Given function is f(t) = 12.4t
Let us assume that Nate works 'x' hours so 4<x<9
And multiplying the hours with his earnings we get the range.
4*12.40=49.6 and 9*12.40=111.6. Let the amount earned be represented by y
Hence, domain can be represented as 4<x<9 and range can be represented as 49.6 < y < 111.6