CO = AO = 32 (Are rays.)
BO = BC + CO = 98 + 32 = 130
AB ⊥ BO
⇒ ΔAOB is a rectangular triangle.
We use Pitagora's theorem.
The angle of depression from the top of the flag pole to point A is 36.2 degrees.
<h3>What is the angle of depression?</h3>
From trigonometric ratio: cos(θ) = Adjacent / Hypotenuse
Given that;
- Adjacent = 25ft
- Hypotenuse = 31ft
- Angle of depression θ = ?
cos(θ) = Adjacent / Hypotenuse
Cos(θ) = 25ft/31ft
Cos(θ) = 0.80645
θ = cos⁻¹( 0.80645 )
θ = 36.2°
Therefore, the angle of depression from the top of the flag pole to point A is 36.2 degrees.
Learn more about angle of depression here: brainly.com/question/11348232
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The coordinates of X are (5, 11).
Solution:
Given points of the line segment are P(2, 2) and T(7, 17)
Let X be the point that partitions the directed line segment PT in the ratio 3 : 2
Using section formula, we can find the coordinate of the point that partitions the line segment.
Section formula:

Here,
and m = 3, n =2
Substitute these in the section formula,




X(x, y) = (5, 11)
The coordinates of X are (5, 11).
Answer:
3 square root of 64 = 24 (clue #2)
9^2=81 (clue #4)
negative square root of 196 = -14 (clue #1)
(-11)^2= -121 (clue #3)
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