Three points on a circle cannot be collinear (on the same line). For that too be possible the circle would have to have infinite radius, which is impossible as nothing is truly infinite. Therefore it would be impossible to pick three points on a line which also lie on a circle. There are no straight sections along the curvature of a circle as then the points could not all be the same distance from the center, which is the definition of a circle.
C) It is impossible.
Answer:Its telling you whats the degree and all you have to do is solve it to get the deggree by doing 15x to the power of 9 which is 38443359375x plus 3x which is 38443359378x
Step-by-step explanation:Its pretty easy.
Answer:
20 hours
Step-by-step explanation:42x8=336 so 2.5x8=20
If you mean by a(t)=2t+9 is the acceleration function then we integrate...
v(t)=2t^2/2+9t+c where c is vo and we are told that that is -7 so
v(t)=t^2+9t-7 integrating again we get:
s(t)=t^3/3+9t^2/2-7t+c where c is the initial position which is 8 so
s(t)=t^3/3+9t^2/2-7t+8 which neatened up as
s(t)=(2t^3+27t^2-42t+48)/6
