Answer:The cost of one month of game-play =$20
Step-by-step explanation:
Let the cost of one month of gameplay be x
Then cost of game-play bought by Angie =3x.....(1)
and Then cost of game-play bought by Kenny=4x......(2)
Cost of each software package =$50......(3)
The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x
⇒240=100+7x.......→(by adding like terms)
⇒140=7x⇒x=20.....→( dividing both sides by 7 )
∴the cost of one month of game-play =$20
In order to make a frequency plot first we need to find the proportion of each outcome.
Total number of results = 15+20+5+5+5 = 50
Frequency of 0 = 15
Proportion of 0 = 15/50 = 0.3
Frequency of 1 = 20
Proportion of 0 = 20/50 = 0.4
Frequency of 2 = 5
Proportion of 2 = 5/50 = 0.1
Frequency of 3 = 5
Proportion of 3 = 5/50 = 0.1
Frequency of 4 = 5
Proportion of 4 = 5/50 = 0.1
Now we need to plot the data on a frequency plot. The x-axis shows the outcomes from 0 to 4 and y-axis shows the frequency of each outcomes. The frequency plot is shown in the figure attached with.
Since Sarah’s age is 2x of Bob’s age (which is 42) Sarah is 84.
Answer: A. Repeated results if the player makes 75% of his shots in the long run.
Step-by-step explanation:
The null distribution is always the opposite of the alternative distribution which in most cases represents the claim or hypothesis which is to be tested or performed. In the scenario given, the challenge is to show that a basketball player has an average higher than that of the NBA. NBA average stands at 75%. The alternative hypothesis is the claim, which is ;
H1 : μ > 75%
THE null is thus :
H0 : μ = 75% ; which means that repeated result of the player will yields an average of 75%