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nika2105 [10]
3 years ago
14

Seed costs for a farmer are $40 per acre for corn and $32 per acre for soybeans. How many acres of each crop should the farmer p

lant if he wants to spend no more than $5,000 on seed

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

40x+32y\leq 5,000\\x\geq 0, y\geq 0

Step-by-step explanation:

Let the number of acre of corn planted =x

Let the number of acre of soybeans planted =y

Seed costs for a farmer are $40 per acre for corn and $32 per acre for soybeans.

  • Seed Cost for x acre of corn = $40x
  • Seed Cost for y acre of soybeans = $32y

The farmer wants to spend no more than $5,000 on seed.

Therefore the linear inequality is:

40x+32y\leq 5,000\\x\geq 0, y\geq 0

Next, we graph the inequality

When$ x=0, y\leq156.25\\When$ y=0, x \leq 125

The graph is attached below.

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1 ton is equivalent to 2000 pounds

we have to find how many pounds 3 3/8 tons are equal to

if 1 ton --> 2000 pounds

we can break down the fraction into 3 + 3/8

then 3 tons --> 2000 x 3 = 6000 pounds

3/8 ton ---> 2000 x 3/8 = \frac{3*2000}{8} = \frac{6000}{8} = 750 pounds

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7 0
3 years ago
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denpristay [2]

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Have a nice day!

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2 years ago
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<h3 /><h3>What is graph?</h3>

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Learn more about this concept here:

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