The answer to the problem is as follows:
x = sin(t/2)
<span>y = cos(t/2) </span>
<span>Square both equations and add to eliminate the parameter t: </span>
<span>x^2 + y^2 = sin^2(t/2) + cos^2(t/2) = 1 </span>
<span>The final step is translating the original parameter limits into limits on x and y. Over the -Pi to +Pi range of t, x varies from -1 to +1, whereas y varies from 0 to 1. Thus we have the semicircle in quadrants I and II: y >= 0.</span>
Answer:
The correct answer if F
Step-by-step explanation:
Hope you have a great day or afternoon :D
Answer:
The dimensions of the rectangle = 60ft by 107ft
Where 60 ft = Width of the playing field
107ft = Length of the playing field
Step-by-step explanation:
A playing field is Rectangular is shape, hence,
The formula for Perimeter of a rectangle = 2(L + W)
P = 334 ft
L = 47 + W
W = W
Hence we input these values in the formula and we have:
334 = 2(47 + W + W)
334 = 2(47 + 2W)
334 = 94 + 4W
334 - 94 = 4W
240 = 4W
W = 240/4
W = 60
There fore, the width of this playing field = 60 ft
The length of this rectangle is calculated as:
47 + W
47 + 60
= 107 ft
The length of this playing field = 107ft
Therefore the dimensions of the rectangle = 60ft by 107ft
I attached a picture with the answer, hope this helps :)
D 22-14=8 14-7=7 7 of 14=50% so i think that’s the best estimate