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3 years ago

10

Which graph represents a positive linear association between x and y?

1 answer:

Ierofanga [76]3 years ago

5 0

Graph A shows a positive linear association between x and y.

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A box without a top is to be made from a rectangular piece of cardboard, with dimensions 11 in. by 16 in., by cutting out square

qaws [65]

The answer is 11.63333

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2 years ago

An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more effic

Diano4ka-milaya [45]

Step-by-step explanation:

ANOVA table Source SS df MS F

p-value Factor 1 12.00 1 12.000 1.20 .3153

Factor 2 8.00 2 4.000 0.40 .6870 Interaction 56.00 2 28.000 2.80 .1384

Error 60.00 6 10.000 Total 136.00 11

Since the p -value for Factor A is greater than 0.1, therefore Factor A is not significant. The p -value for Factor B is greater than 0.1, therefore Factor B is not significant. It should be noted that for P-value of both Factor and Factor B to be significant, each factor must not be greater than 0.1

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2 years ago

4 g is equivalent to:

V125BC [204]

Answer:4000 mg

Step-by-step explanation:

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2 years ago

Plzzz answer thisss

Nitella [24]

Answer:

I think it's B

Step-by-step explanation:

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2 years ago

How to find nth term for a sequence of following numbers;

Phantasy [73]

Let $a_n$ denote the given sequence. $a_n$ has forward differences

{9 - 1, 36 - 9, 100 - 36, ...} = {8, 27, 64, ...} = {2^3, 3^3, 4^3, ...}

If we call the sequence of forward differences $b_n$ , then for $n\ge1$ ,

$b_n=(n+1)^3$

$b_n$ is defined in terms of $a_n$ for all $n\ge1$ by

$b_n=a_{n+1}-a_n$

and so $a_n$ is defined recursively by

$a_n=\begin{cases}a_1=1\\a_{n+1}=a_n+(n+1)^3&\text{for }n\ge1\end{cases}$

We can deduce a pattern for the general $n$ -th term:

$a_2=a_1+2^3$

$a_3=a_2+3^3=a_1+\displaystyle\sum_{i=1}^2(i+1)^3$

$a_4=a_3+4^3=a_1+\displaystyle\sum_{i=1}^3(i+1)^3$

and so on, up to

$a_n=a_1+\displaystyle\sum_{i=1}^{n-1}(i+1)^3$

We can simplify the right hand side a bit, noticing that $a_1=1=1^3$ matches $(i+1)^3$ for $i=0$ :

$a_n=\displaystyle\sum_{i=0}^{n-1}(i+1)^3$

and to simplify things a bit more, we shift the index of summation:

$a_n=\displaystyle\sum_{i=1}^ni^3$

You should know that the right side has a nice closed form (look up "Faulhaber's formula" if you don't):

$a_n=\dfrac{n^2(n+1)^2}4$

3 0

3 years ago