Which graph represents a positive linear association between x and y?
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<u>Question Completion</u>
(a)What is your null hypothesis?
(b)What is your expected phenotypic ratio based on Mendelian inheritance?
(c)Calculate the expected number of flowers you should have gotten based on the Mendelian inheritance. Then calculate a chi-square value, degrees of freedom, and a p-value.
- Chi-square statistic: _____
- Degrees of freedom (# phenotypes -1):
- P-value:
(d)Interpret your results. Do you reject it or fail to reject your null hypothesis (please restate the null)?
Answer:
(a)
(b)9:3:3:1
(c)
- Chi-square statistic: 3.8914
- Degrees of freedom (# phenotypes -1) =3
- P-value: 0.2734
(d)We fail to reject the null hypothesis.
Step-by-step explanation:
In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flowers (e). An F2 generation was created by crossing two F1 individuals (each BbEe).
(a)The null hypothesis is:
(b)The gametes are BE, Be, bE and be.
The offsprings are presented in the table below:
The expected phenotypic ratio based on Mendelian inheritance
BE:Be:bE:be=9:3:3:1
(c)
Therefore:
- Chi-square statistic: 3.8914
- Degrees of freedom (# phenotypes -1): 4-1 =3
- P-value: 0.2734
(d) Our null hypothesis is:
Since p>0.05, the given data fit the predicted phenotypic ratio.
We, therefore, fail to reject the null hypothesis.
The difference in the observed and expected are sosmall that they can be attributed to random chance.
Step-by-step explanation:
We can model the annual consumption of iron by the equation
c = 900 million tons x , where
n is the number of years after 1993 and
c is the consumption for that year.
An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.
This equation simplifies to
C = 900 million tons x (1.025^n - 1) / ln(1.025), where
x is a dummy variable and
C is the total consumption of iron n years after 1993.
Let R be the amount of iron remaining at n years after 1993, so
R = 480 billion tons - C
R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)
We need to find the value of n when R is 0, so
0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)
Simplify this equation to obtain
n = 107.4
So the iron will run out in the year 1993 + 107 = 2100