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3 years ago

Which graph represents a positive linear association between x and y?

Mathematics

1 answer:

Ierofanga [76]3 years ago

5 0

Graph A shows a positive linear association between x and y.

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Find the number of letters from the word MAXIMUM where two consonants cannot occur. (Permutation)

Hunter-Best [27]

Answer:

Step-by-step explanation:

In word MAXIMUM, consonants are M & X. According to the question itself, consonants should not occur together.

So, we have to put vowels at each even position; only then the condition will be satisfied.

We can put this in 3! ways (permutations of A, I & U).

For odd positions we can put 3-M's & a X. Total ways is 4!/3! (as repetitions of M).

Hence, the answer is 4!/3! x 3! = 24 ways.

24=4!.

5 0

2 years ago

16. An experiment is carried out to determine how different pH values of soil will affect the growth of tomato plants. In this

svetoff [14.1K]

Step-by-step explanation:

2. Amount of soil provided.

In order to give different pH values of the soil, the amount of soil can directly affect this independent variable.

6 0

3 years ago

Write the equation in slope-intercept form. y = 6(x + 2) + 5x

sveticcg [70]

Answer:

y=11x+12

Step-by-step explanation:

y = 6(x + 2) + 5x

y=6x+12+5x

y=11x+12

in slope interception form= y=mx+c

y=11x+12

5 0

2 years ago

Read 2 more answers

Iv) 6x+3y=6xy 2x + 4y= 5xy

Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5 - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

$y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}$

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0

3 years ago

Solve the system of equations. 2y+7x=−5 5y−7x=12

3241004551 [841]

We can solve this by substitution method.

Look at the second equation. If we rearrange to find 7x, we can substitute in the value into the first equation.

$5y-7x=12$

$5y-7x-12=0$

$5y-12=7x$

Therefore, $7x=5y-12$

Now replace the 7x in the first equation with 5y - 12:

$2y+7x=-5$ (substitute in 7x = 5y - 12)

$2y+(5y-12)=-5$

$7y-12=-5$

$7y=7$

$y=1$

Now that we know y, we can find x by substituting in y = 1 into any equation we want. I will use the equation: 7x = 5y - 12

$7x=5y-12$ (substitute in y = 1)

$7x=5(1) -12$

$5x=5-12$

$7x=-7$

$x=-1$

__________________________________________________________

Answer:

$y=1\\x=-1$

4 0

3 years ago