V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)

(dv/dt)*(dt/dh) = dv/dh

dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)

5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)

then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))

5 0

2 years ago

A construction crew is extending the length of the center line on a highway. The length of the line starts out as 6 meters long,

baherus [9]

Gradient of line,m=(17-6)/(20-0)=11/20

finding equation of line using a point (20,17)

y-17=11/20(x-20)
y-17=(11/20x)-11
y=11/20x+(17-11)
y=(11/20)*x+6

4 0

3 years ago

Read 2 more answers

Find the values of x and y

vitfil [10]

Hi there!

$\large\boxed{y = 12, x = 3}$

The two trapezoids are similar, so we can determine a common scale factor:

OL/UR = NM/TS

9/3 = 6/2

3 = 3

Trapezoid ONML is 3x larger than UTSR, so:

RS = 4, LM = y

3RS = LM

3 · 4 = y = 12.

Find x using the same method:

3UT = ON

3(2x+1) = 4x + 9

6x + 3 = 4x + 9

2x = 6

x = 3.

4 0

2 years ago