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3 years ago

Convert polar equation to rectangular coordinates θ = − (9π/ 2)

1 answer:

7 0

Visualize pi/2 as 90° on the unit circle. this has no real component, only imaginary. same for 3pi/2, or -pi/2 as shown in this equation:

$- \frac{ \pi}{2} = 0 - i$

as you move around the unit circle, you'll find that 9pi/2 is the same angle as pi/2.

Thus, the rectangular coordinates are:
$- \frac{9\pi}{2} = 0 - i$

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The ratio between the number of students (s) on a field trip and the number of teachers (t) on the field trip is 21/4. There are

RoseWind [281]

Answer:

Step-by-step explanation:

If there needs to be 4 teachers per 21 students, you would divide the total amount of students by 21 and multiply that answer by 4. SO...:

84 ÷ 21 = 4 groups of 21 students.

4 groups × 4 teachers = 16

*** Answer***

16 TEACHERS

5 0

3 years ago

1+Sin/Cos + Cos/1+Sin = 2Sec

Bond [772]

Step-by-step explanation:

Consider the left-hand side:

$\dfrac{1+\sin{\theta}}{\cos{\theta}} + \dfrac{\cos{\theta}}{1+\sin{\theta}}$

$\:\:\:\:= \dfrac{(1+\sin{\theta})^2 + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:=\dfrac{1+2\sin{\theta}+\sin^2{\theta} + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:=\dfrac{2+2\sin{\theta}}{\cos{\theta}(1+\sin{\theta})} =\dfrac{2(1+\sin{\theta})}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:= \dfrac{2}{\cos{\theta}} = 2\sec{\theta}$

7 0

3 years ago

Find the number of meters each record holder ran in one second of each event. Round to the nearest tenth.

eimsori [14]

To find the answers to each you have to divide the total distance by the total time to get the answer in meters/sec, which would be distance run per sec.
A. 200m/19.30sec = 10.36 meters per second
B. 400m/43.18sec = 9.26 meters per second
C. 100m/9.69sec = 10.32 meters per second

3 0

3 years ago

The translation (x,y)(x+3,y-3) maps TUVW onto T'U'V'W. What translation maps T'U'V'W onto TUVW?

leva [86]

Mapping T'U'V'W' onto TUVW is just the backwards translations of TUVW to T'U'V'W'.

The translation (x + 3, y - 3) moves all x-coordinates 3 units to the right and all y-coordinates 3 units down.

So if we want to move the figure back to its original position, we do the opposite: move all x-coordinates 3 units to the left and y-coordinates 3 units up.
This is expressed as (x - 3, y + 3).

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3 years ago

Read 2 more answers

Graph the solution to this inequality on the number line. 8x <(with a line under) 56

Jobisdone [24]

Answer:

the answer is shown in the image above

4 0

2 years ago