Answer: B
Step-by-step explanation: if you divide 27/30 by 3 you get 9/10
567/71 because passengers/(train cars/passengers) = train cars
71 x 7 = 497 (not enough)
71 x 8 = 568 (enough)
Answer: 8 train cars
Answer:
t = -5
Step-by-step explanation:
Solve for t:
5 (t - 3) - 2 t = -30
Hint: | Distribute 5 over t - 3.
5 (t - 3) = 5 t - 15:
5 t - 15 - 2 t = -30
Hint: | Group like terms in 5 t - 2 t - 15.
Grouping like terms, 5 t - 2 t - 15 = (5 t - 2 t) - 15:
(5 t - 2 t) - 15 = -30
Hint: | Combine like terms in 5 t - 2 t.
5 t - 2 t = 3 t:
3 t - 15 = -30
Hint: | Isolate terms with t to the left hand side.
Add 15 to both sides:
3 t + (15 - 15) = 15 - 30
Hint: | Look for the difference of two identical terms.
15 - 15 = 0:
3 t = 15 - 30
Hint: | Evaluate 15 - 30.
15 - 30 = -15:
3 t = -15
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 3 t = -15 by 3:
(3 t)/3 = (-15)/3
Hint: | Any nonzero number divided by itself is one.
3/3 = 1:
t = (-15)/3
Hint: | Reduce (-15)/3 to lowest terms. Start by finding the GCD of -15 and 3.
The gcd of -15 and 3 is 3, so (-15)/3 = (3 (-5))/(3×1) = 3/3×-5 = -5:
Answer: t = -5
Answer:
<u>a) x = 3</u>
<u>b) z = 10</u>
<u>c) p = 2</u>
<u>d) x = 7</u>
<u>e) u = 1</u>
Step-by-step explanation:
a) 2x = 6
Despejamos x dividiendo por 2 a amabos lados de la eacuacion.
(2/2)x = 6/2
<u>x = 3</u>
Si remplazamos x en la ecuación original:
2(3)=6
6 = 6
Queda demostrado.
b) 10 + z = 20
Despejamos z restando 10 en amabos lados de la eacuacion.
10-10+z = 20-10
<u>z = 10</u>
Si remplazamos z en la ecuación original:
10 + 10=20
20 = 20
Queda demostrado.
c) p + 9 = 11
Despejamos p restando 9 en amabos lados de la eacuacion.
p + 9 - 9 = 11-9
<u>p = 2</u>
Si remplazamos p en la ecuación original:
2 + 9 = 11
11 = 11
Queda demostrado.
d) 3x + 8 = 29
Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.
3x+8-8 = 29-8
3x = 21
(3/3)x = 21/3
<u>x = 7</u>
Si remplazamos x en la ecuación original:
3(7) + 8 = 29
21 + 8 = 29
29 = 29
Queda demostrado
e) 2u + 8 = 10
Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.
2u+8-8 = 10-8
2x = 2
(2/2)x = 2/2
<u>x = 1</u>
Si remplazamos x en la ecuación original:
2(1) + 8 = 10
2 + 8 = 10
10 = 10
Queda demostrado
Espero te haya sido de ayuda!
Answer:
4 4/5 miles
Step-by-step explanation:
We want to multiply 4/5 * 6
4/5 * 6/1
24/5
We need to change this back to a mixed number
5 goes into 24 4 times (4*5 = 20 with 4 left over)
4 4/5 miles