To get rid of
, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write
as a product of 2 polynomials:
From this we know, that
is the solution. Another solutions (complex roots) are the roots of quadratic equation.
There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.
Even means the graph is symmetric about the y-axis
The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)
because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).
Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
Answer:
13
Step-by-step explanation:
Replace X with 2
Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)
g(x) = 3(2)^2 – 2(2) + 5
Next conduct PEMDAS
Exponents are first so solve 2^2 which is 2 x 2 = 4
g(x) = 3(4) – 2(2) + 5
Next step is multiplication multiply 3 x 4 and 2x2
g(x) = 12 – 4 + 5
conduct adding and subtracting left from right
g(x) = 13
Answer:
El período paleolítico corresponde a 
de la época prehistórica.
Step-by-step explanation:
En primer lugar, se determina la extensión de tiempo, medida en años, tanto de la época prehistórica como el período paleolítico: (Nótese que el signo negativo significa a.C.)
Época Prehistórica
Período Paleolítico
La fracción de la época prehistórica que corresponde al período paleolítico es:
El período paleolítico corresponde a de la época prehistórica.
Amount of Interest = $36
Rate of interest = 3% per annum
Total time period for which the money was invested = 3 years
Let us assume the Principal amount = x
Then
Interest = Principal * Rate of Interest * time
36 = x * 3% * 3
36 = 9x/100
36 * 100 = 9x
3600 = 9x
x = 3600/9
= 400
So the initial sum of the money that was invested was $400.
