Let the initial count of his fish be n.
He gives away 2/3 of these fish: 2n/3, leaving n/3 fish.
He gives away 2/5 of these remaining n/3 fish: (2/5) times (n/3), or
2n
--- , meaning that (3/5) times (n/3) fish are left.
15
(3/5)(n/3) = n/5 fish left = 30 fish. Thus, n = 150 fish.
Be certain to check this answer!
Answer:
She will have 6 pieces of ribbon
Step-by-step explanation:
She will have 0.64 inches of ribben left over
Answer:
f^−1(x)=1/3+lnverse(x)/3inverse(2)
Step-by-step explanation:
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫
➷ Only the second one because only that one has -5, 5 going through it
✽
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
DOGE
-4 1/2 = -4.5
5.6 = 5.6
-2 3/8 = -2.375
1.35 = 1.35
If we order it from least to greatest, we would get:
-4 1/2, -2 3/8, 1.35, 5.6
If we order it from greatest to least, we would get:
5,6, 1.35, -2 3/8, -4 1/2
