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3 years ago

A line with a slope of -2 crosses the y-axis at (0,3). The equation of the line is

Mathematics

2 answers:

san4es73 [151]3 years ago

8 0

In slope-intercept form, the line's equation is
y = -2x + 3

Adding 2x to the equation gives you ...
c) 2x + y = 3

Flauer [41]3 years ago

5 0

the answer is C hope it helps xD

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

4 years ago

FIRST ONE TO ANSWER GETS BRAINLIEST!!!!

-Dominant- [34]

Answer:

The maximum distance traveled is 4.73 meters in 0.23 seconds.

Step-by-step explanation:

We have that the distance traveled with respect to time is given by the function,

$d(t) = 4.9t^2-2.3t+5$ .

Now, differentiating this function with respect to time 't', we get,

d'(t)=9.8t-2.3

Equating d'(t) by 0 gives,

9.8t - 2.3 = 0

i.e. 9.8t = 2.3

i.e. t = 0.23 seconds

Substitute this value in d'(t) gives,

d'(t) = 9.8 × 0.23 - 2.3

d'(t) = 2.254 - 2.3

d'(t) = -0.046.

As, d'(t) < 0, we get that the function has the maximum value at t = 0.23 seconds.

Thus, the maximum distance the skateboard can travel is given by,

$d(t) = 4.9\times 0.23^2-2.3\times 0.23+5$ .

i.e. $d(t) = 4.9\times 0.0529-2.3\times 0.23+5$ .

i.e. $d(t) = 0.25921-0.529+5$ .

i.e. d(t) = 4.73021

Hence, the maximum distance traveled is 4.73 meters in 0.23 seconds.

5 0

3 years ago

answer asap!!!! How much time will Alex need to walk to his school, which is 2 1/4 miles away from his house, if he would walk w

maxonik [38]

Answer:

0.89h or 53 minutes

Step-by-step explanation:

2m/h / 2.25m

= 0.89h

4 0

3 years ago

Read 2 more answers

Can anyone show me the steps in order solve this problem

STatiana [176]

M∠A = 42° [isosceles triangle]

m∠B = 180 - 42 - 42 = 96° [in a triangle, the three interior angles always add to 180°]

m∠C = 180 - 96 - (x+12)
m∠C = 84 - x - 12
m∠C = 72 - x

2x+9 + 3x-1 + 72-x = 180
4x + 80 = 180
4x = 180 - 80
4x = 100
x = 100/4
x = 25

m∠C = 72 - x = 72 - 25 = 47°

<span>I hope this helped</span>

8 0

3 years ago

False

dedylja [7]

It’s true you can give the other person it tho

5 0

3 years ago