Answer:
Yes it will be appropriate to model the distribution of a sample mean with a normal model
Step-by-step explanation:
Given that the population is not normal, and the sample is sufficiently large, according to the Central Limit theorem, the distribution of the mean pf the sampling distribution will be approximately normal not withstanding the population from which the sample is obtained. Therefore, the mean, 
, and the standard deviation, 
, of the sample will be equal to the mean, μ, and standard deviation, σ, of the of the population
Therefore, it will be appropriate to model the distribution of a sample mean with a normal model
Answer: (0, -6) , (1 , -4) , ( 2 , -2)
Step-by-step explanation:
Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB=DEAB=DEA, B, equals, D, E, BC=EFBC=EFB, C, eq
Novay_Z [31]
Answer:
- (A) AB = DE and segments with same length are congruent
Step-by-step explanation:
Justification of step 1 is based on the congruence of segments AB and DE.
<u>Therefore correct choice is the first one:</u>
- (A) AB = DE and segments with same length are congruent
Hello!
A isn't showing any real property. B shows the commutative property, and C shows the associative. With D, if you multiply the parentheses by the outside number, you get 36+8, which is using the distributive property.
Therefore, our answer is D.
I hope this helps!
Answer:
8 = x²
Step-by-step explanation:
Logarithmic form: logₓ(8) = 2
Exponential form: 8 = x²
