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3 years ago

Evaluate: 2a + 4b when a = 10 & b = 6

Mathematics

1 answer:

Tcecarenko [31]3 years ago

7 0

Answer: Option C: 44

Step-by-step explanation:

so, here we have the equation:

H(a,b) = 2a + 4b

"evaluate" means change the values of the variables for specific values, here we must replace the "a" for 10, and the "b" for a 6.

So we have:

H(10, 6) = 2*10 + 4*6 = 20 + 24 = 44

You might be interested in

Use distributive property to write an expression that is equivalent to 6(u+12)

nirvana33 [79]

Answer:

6u + 72

Step-by-step explanation:

6(u + 12)

Distribute 6 to u and 12

6(u) + 6(12)

6u + 72

6 0

3 years ago

The graphs of the equation y = 4x + 1 and y - kx = 10 are perpendicular when k = _______?

Ann [662]

Answer:

$k=-\frac{1}{4}$

Step-by-step explanation:

we have

Line 1

$y=4x+1$

Equation in slope intercept form

The slope is equal to

$m_1=4$

Line 2

$y-kx=10$

$y=kx+10$

Equation in slope intercept form

The slope is equal to

$m_2=k$

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)

$m_1*m_2=-1$

substitute

$(4)(k)=-1$

$k=-\frac{1}{4}$

3 0

3 years ago

Jay is hanging 160 feet of Christmas garland on the three sides (two on the width and one on the length) of fencing that enclose

Setler [38]

The length of the fencing is 62.4 feet.

The width of the fencing is 17.6 feet.

Given,

The measurement of the Christmas garland = 160 feet

The width of the fencing = w

The length of the fencing, l = 4w - 8

We have to find the length and width of the fencing.

Here,

Perimeter can be taken as 160. Because garland will cover the entire fencing.

Perimeter = 2(l + w)

160 = 2(4w - 8 + w)

160 = 2(5w - 8)

160/2 = 5w - 8

80 + 8 = 5w

88/5 = w

width = 17.6 feet

Now,

l = 4w - 8

l = 4 × 17.6 - 8

l = 70.4 - 8

length = 62.4 feet

That is,

The length of the fencing is 62.4 feet.

The width of the fencing is 17.6 feet.

Learn more about perimeter here:

brainly.com/question/13023749

#SPJ1

3 0

1 year ago

One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides

Elina [12.6K]

<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

The side of the square is 10 ft.
One of the vertices of an equilateral triangle is on the vertex of a square.
Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

$\mathbf{(1)} \ x^2=100+y^2$

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

$y+(10-y)=10$

Therefore, for Triangle 3, we have that by Pythagorean theorem:

$(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2$

Matching equations (1) and (2):

$2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0$

Using quadratic formula:

$y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68$

Finding x from (1):

$x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft$

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0

3 years ago

Read 2 more answers

How would you solve this? Please give an explanation.

Neporo4naja [7]

The <em>first three</em> elements of the <em>recursive</em> series are 6, 10, 8. (Correct choice: B)

<h3>How to generate values from a recursive function</h3>

In this question we have a kind of <em>recursive</em> function known as Fibonacci's function, where a value of the series is generated from at least <em>immediately previous</em> elements. In this case, we need to find the <em>first</em> three elements from the <em>fifth</em> and <em>fourth</em> elements of the series:

$a_{n-2} = a_{n-1} - a_{n} + 4$

a₄ = a₅ - a₆ + 4

a₄ = - 2 - 0 + 4

a₄ = 2

a₃ = a₄ - a₅ + 4

a₃ = 2 - (- 2) + 4

a₃ = 8

a₂ = a₃ - a₄ + 4

a₂ = 8 - 2 + 4

a₂ = 10

a₁ = a₂ - a₃ + 4

a₁ = 10 - 8 + 4

a₁ = 6

The <em>first three</em> elements of the <em>recursive</em> series are 6, 10, 8. (Correct choice: B)

To learn more on recursive series: brainly.com/question/8972906

#SPJ1

4 0

2 years ago