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2 years ago

What is the least angle measure by which this figure can be rotated so that it maps onto itself?

Mathematics

2 answers:

Vinil7 [7]2 years ago

7 0

T think its 90 hope this helpes

Romashka [77]2 years ago

7 0

Answer-

90° is the least angle measure by which this figure can be rotated so that it maps onto itself

Solution-

As the figure has two axis of symmetry, placing x and y axis such that the origin lies on its centroid.

Angle between x axis and y axis is 90°.

So rotating any degree which is a multiple of 90 i.e 90°, 180°, 270°, 360°...... would yield the original figure.

Therefore, 90° is the least angle measure by which this figure can be rotated so that it maps onto itself.

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Serga [27]

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3 years ago

Definitions of ASA SAS AAS, can someone dumb it down plz?

Veseljchak [2.6K]

Answer:

Hope this helps.

Step-by-step explanation:

So for ASA, the two triangles have to have two angles congruent, and in the middle of those angles, they have to have a line that's congruent.

For SAS, the two triangles have to have two lines congruent, and in the middle of those lines, they have to have an angle that's congruent.

For AAS, the two triangles have to have two angles congruent, but the line that's congruent has to be on the side, not in the middle.

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3 years ago

What is the gcf of 28 and 60

Vikki [24]

Answer:

Step-by-step explanation:

We need to find the factors of each number

28 -

1x28

2x14

4x7

60 -

1x60

2x30

3x20

4x15

5x12

6x10

then we need to find the largest number they have in common

in this case it is 4

3 0

3 years ago

Write the decimal in simplest fractional form: 3.05

Sidana [21]

61/20 is the answer.

5 0

2 years ago

Read 2 more answers

Which number line represtents the solution to |x+4|=2?

vlada-n [284]

Answer:

Points -2 and -6 on the number line are the two solutions.

Step-by-step explanation:

Use the definition of absolute value as a starting point

$|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x$

To solve the equation, you need to treat the two cases as above:

$|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2$

The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:

$|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x$

Again, the second solution -6 complies with the requirement that x<-4, so it is valid.

7 0

2 years ago