Answer:
The point Q(6,7) lie outside the circle.
Step-by-step explanation:
We know that, the general equation of a circle,
---------(1)
Centre is (-g, -f) = (2,4) (given)
So, -g = 2⇒g = -2
and, -f = 4⇒f = -4
Putting the value of g and f in equation(1), we get
The point L(0,8) is on the circle, the this point can satisfy the above equation.
So,
Now, the equation of circle is
Putting the and in the above equation, we get
5, which is greater than 0.
So, the point Q(6,7) lie outside the given circle.