$20 minus $15 = $5 difference
$5 divided by $0.20 = 25 checks
*Now the accounts are even, except I haven't done the checks for the second account.*
25 checks times $0.10 = $2.50
$2.50 divided by $0.20 = 12.5 checks (round up in this case to 13)
*Now, you need to do 13 more checks on the second account*
13 checks times $0.10 = $1.30
$1.30 divided by $0.20 = 6.5 checks (round up in this case to 7)
*Now, you need to do 7 more checks on the second account*
7 checks times $0.10 = $0.70
$0.70 divided by $0.20 = 3.5 checks (round up in this case to 4)
*Now, you need to do 7 more checks on the second account*
4 checks times $0.10 = $0.40
$0.40 divided by $0.20 = 2 checks
*Now, you need to do 2 more checks on the second account*
2 checks times $0.10 = $0.20
$0.20 divided by $0.20 = 1 check
*Now, you need to do 1 more checks on the second account*
1 checks times $0.10 = $0.10
$0.10 divided by $0.20 = 0.5 checks (round up in this case to 1)
*Now, you need to do 1 more checks on the second account*
1 checks times $0.10 = $0.10
$0.10 divided by $0.20 = 0.5 checks
25 + 13 + 7 + 4 + 2 + 1 + 1 = 53 checks
Check your work!
Account #1- $15 + (53 times $0.20) = $25.60
Account #2- $20 + (53 times $0.10) = $25.30
Answer
53 checks
Number 1 and 2 are simillar and 5 and 6 are not simmilar
Answer:
Therefore the length FG is 16 unit.
Step-by-step explanation:
Given:
∠E ≅ ∠G = 90°
DF bisects ∠EDG
Bisector Divide the angle in EQUAL parts
∴∠EDF ≅ ∠GDF
FE = n +5
FG = 2n - 6
To Find:
FG = ?
Solution:
In ΔEDF and ΔGDF
∠E ≅ ∠G = 90° ……….{Given}
∠EDF ≅ ∠GDF ..……..{DF bisects ∠EDG}
DF ≅ DF ……….{Reflexive Property}
ΔEDF ≅ ΔGDF ….{ By Angle-Angle-Side Congruence test}
∴ FE ≅ FG .....{corresponding parts of congruent triangles are congruent}
Substituting the values of FE and FG we get
Substituting ' n ' in FG we get
Therefore the length FG is 16 unit.
B I think about 80 percent sure lol but hope this helps
Answer:
-6/7p+1/7
Step-by-step explanation:
