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3 years ago

6

How to find the position function from the velocity function?

1 answer:

Gre4nikov [31]3 years ago

5 0

The velocity is the derivative of the position with respect to time, which is f′(t). Once you have that function, you set it to 0 and solve for t to find the time at which the velocity is zero, and then you can use that time to find the position of the object at that moment. I hope this helps

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f(x) = -4x^2+12x-9f(x)=−4x 2 +12x−9f, left parenthesis, x, right parenthesis, equals, minus, 4, x, squared, plus, 12, x, minus,

Olin [163]

Answer:

The graph has only one x-intercept

Step-by-step explanation:

we have

$f(x)=-4x^2+12x-9$

we know that

The discriminant of a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$D=b^{2}-4ac$

in this problem we have

$f(x)=-4x^2+12x-9$

so

$a=-4\\b=12\\c=-9$

substitute

$D=12^{2}-4(-4)(-9)$

$D=144-144$

$D=0$

The discriminant is zero

That means ----> The quadratic equation has one real solution

The graph has only one x-intercept

3 0

3 years ago

May I please have help? Thank you! And can you please tell me how you got the answer? Thank you again!

FinnZ [79.3K]

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$2(1 \frac{3}{4} )$

multiply the following

add the sum (3.5+0.55)

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3 years ago

Functions. Type the correct domain in the box

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3 years ago

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Answer:

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