3 years ago

What are the solutions to the equation 6x^2 - x - 40 = 0?

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

A
That’s the real answer

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Solve for x<br>a.81<br>b.41<br>c.1681

Jlenok [28]

A=9 , b=40

Pythagorean theorem
$a^2+b^2=x^2 \\\\ x=\sqrt{a^2+b^2}=\sqrt{9^2+40^2}=\sqrt{81+1600}=\sqrt{1681}=\sqrt{41^2}=41$

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3 years ago

F(x) = 7|x| awnser the question for some points

Eddi Din [679]

f(x) = 7|x|

if x= 1

then f(x) = 7

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Create a memory device to help you remember the quadratic formula. The device could be a song, drawing, rhyme, mnemonic device,

Lostsunrise [7]

Answer:

q-u-a-d-r-a-t-i-c f-o-r-m-u-l-a

Step-by-step explanation:

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3 years ago

Helpp please quick!!!!

lesya692 [45]

Answer:

A) Leg

Step-by-step explanation:

In a right triangle, the side that is opposite of the right angle is the hypotenuse. It is also the longest side of the triangle.

Since side 'a' makes up a right angle and it's a shorter piece, it is a leg of the triangle.

Hope this helps.

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3 years ago

An experiment observing the growth of two germ strand populations finds these patterns.

Mice21 [21]

Answer:

$R(x) = (1.3)^{3x-8}$

Step-by-step explanation:

Given

$A(x) = (1.3)^{x + 9}$

$B(x) = (1.3)^{4x + 1}$

Required

Ratio B(x) to A(x)

This is calculated as:

$R(x) = B(x) : A(x)$

Express as fraction

$R(x) = \frac{B(x) }{A(x)}$

Substitute: $A(x) = (1.3)^{x + 9}$ and $B(x) = (1.3)^{4x + 1}$

$R(x) = \frac{(1.3)^{4x+1}}{(1.3)^{x+9}}$

Apply law of indices

$R(x) = (1.3)^{4x-x+1-9}$

$R(x) = (1.3)^{3x-8}$

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3 years ago