3 years ago

What are the solutions to the equation 6x^2 - x - 40 = 0?

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

A
That’s the real answer

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The height h in feet of a ball thrown vertically upward from the top of a 288-foot tall building is given by h=288+48t-16t^2 whe

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6 sec can take penny to strike the ground.

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Given data:

$H_0=288$ feet

$V_0=48$ feet

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Re-arrange the terms from greatest degree to smallest degree.

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$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a = –16, b = 48, c = 288

$$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}$

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$$t=\frac{-48\pm \sqrt{20736}}{-32}$

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Now, write find two t's using plus and minus operation.

$$t=\frac{-48+144}{-32},\ \ t=\frac{-48-144}{-32}$

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Therefore t = 6.

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