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3 years ago

What’s the ratio of the length side ?

Mathematics

1 answer:

Degger [83]3 years ago

8 0

if the triangles are similar, all the sides have the same ratio

the easiest side to solve is AB and DE

AB is 4 and DE is 2

AB/DE=4/2=2/1

so BC/EF is also 2/1

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What fraction of a pint is 7 fluid ounces? 1 pint = 16 fluid ounces

LenKa [72]

Well since the whole (1 pint) is 16 fluid ounces (fl oz) and we only have 7 fl oz, the fraction is 7 over 16; 7/16. This fraction can't be simplified, so 7/16 is in simplest form.
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2 years ago

Find (f•g) (k) equations in red letters

chubhunter [2.5K]

The answer is (f . g)(x) = - (34k + 17k⁷ + 17k⁵ + 40k³ + 20k² + 60).

Remember that :

(f . g)(x) = f(x) × g(x)

Hence :

(f . g)(x) = (2k³ + k² + 3)(-17k⁵ - 20)
(f . g)(x) = -34k⁸ - 17k⁷ - 17k⁵ - 40k³ - 20k² - 60
(f . g)(x) = - (34k + 17k⁷ + 17k⁵ + 40k³ + 20k² + 60)

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1 year ago

Which value of x makes the equation 5x – 2 + 3x = 14 true?

Alina [70]

Answer:

Step-by-step explanation:

5x+3x=14+2

8x=16

x=2

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5 0

2 years ago

if you blend 2 scoops of chocolate ice cream with 1 cup of milk, you get a milkshake with a stronger chocolate flavor than if yo

Tpy6a [65]

If you did 3 scoops of ice-cream and 2 cups of milk you would have 2times the amount of milk and only 1 1/2 times the amount of ice-cream then if you did 1 cup of milk and 2 scoops of ice-cream

6 0

2 years ago

Read 2 more answers

A confectioner has 300 pounds of a chocolate that is 1 part cocoa butter to 7 parts caramel. How much chocolate that is 1 part c

anygoal [31]

Let's call our unknown quantity $n$ . We'll need to add $n$ lbs of chocolate with a 1/15 ratio of cocoa butter to caramel to 300 lbs of chocolate with a 1/7 ratio of cocoa butter to caramel to yield $300+n$ lbs of chocolate with a 1/9 ratio of cocoa butter to caramel. We can set this up as an equation, but it's important to note something first: the ratio of the caramel to the cocoa butter is provided, but this is not the same thing as the fraction of the chocolate the cocoa butter takes up.

The 300 pounds of chocolate have 1 + 7 = 8 parts of cocoa butter and caramel total, which means that cocoa butter takes up 1/8 of those total parts; the $n$ pounds we're adding on has 1 + 15 = 16 total parts, which means the cocoa butter takes up 1/16 of those; and the $300+n$ pounds being produced have 1 + 9 = 10 total parts, so the cocoa butter takes up 1/10 of those parts. With this in mind, we can set up the following equation:

$300\big( \frac{1}{8}\big)+n\big( \frac{1}{16}\big)=(300+n)\big( \frac{1}{10}\big)$

which we can rewrite as

$\frac{300}{8}+ \frac{n}{16}= \frac{300+n}{10}$

From here, it would be helpful to combine the fractions on the left side of the equation. To do this, we'll convert the denominator of $\frac{300}{8}$ to 16, multiplying it by $\frac{2}{2}$ to obtain the fraction $\frac{600}{16}$ . Combining that with $\frac{n}{16}$ , we have:

$\frac{600+n}{16}= \frac{300+n}{10}$

To get rid of the denominator on the left, we'll multiply both sides of the equation by 16, and to eliminate the one on the right, we'll multiply both sides by 10:

$(10)(16)\big( \frac{600+n}{16}\big)=\big( \frac{300+n}{10}\big)(10)(16)$

Simplifying:

$10(600+n)=(300+n)16\\ 6000+10n=4800+16n$

And finally, we solve for $n$ :

$6000-4800=16n-10n\\ 1200=6n\\ 200=n$

So, the confectioner needs 200 lbs of chocolate that's 1 part cocoa butter and 15 parts caramel.

8 0

2 years ago